Question

我有两张桌子。 visitor_details，包含id，scanner_，时间列和visitor_info，其中包含scanner_名称，姓氏列

我想回来 id，姓名，姓氏，表格中的时间

我写过这个但是没有用

$result = mysql_query("SELECT visitors_details.id AS id, 
visitors_info.name AS name, visitors_info.surname AS surname, visitors_details.time 
AS time FROM visitors_details AS d LEFT JOIN visitors_info AS i ON 
d.scanner_id=i.scanner_id ");

echo "<table border='1'>
<tr>
<th>id</th>
<th>name</th>
<th>surname</th>
<th>Time</th>
</tr>";

while($row = mysql_fetch_array($result))
  {
 echo "<tr>";
 echo "<td>" . $row['id'] . "</td>";
 echo "<td>" . $row['name'] . "</td>"; 
 echo "<td>" . $row['surname'] . "</td>";
 echo "<td>" . $row['time'] . "</td>";
  echo "</tr>";
  }
   echo "</table>";

任何想法??

Answer 1

尝试此查询

 $result = mysql_query("SELECT d.id , i.name , i.surname , d.time 
                       FROM visitors_details AS d LEFT JOIN visitors_info AS i 
                        ON d.scanner_id=i.scanner_id ");

Answer 2

最好为您的代码启用一些调试，如下所示：

<?php
error_reporting(E_ALL);
$sql = "
SELECT d.id AS id, i.name AS name, i.surname AS surname, d.time  AS time 
  FROM visitors_details AS d 
  LEFT JOIN visitors_info AS i ON d.scanner_id=i.scanner_id
";

$result = mysql_query($sql);
if (!$result) {
    die('Invalid query: ' . mysql_error());
}

?>

Answer 3

添加此项以捕获错误。节省了大量时间：

if(!$result) {
    echo mysql_error();
}

php mysql从2个表中的列中选择Join

3 个答案: