我需要检查目录中图像的尺寸。目前它有大约700张图像。 我只需要检查尺寸，如果尺寸与给定尺寸不匹配，它将被移动到另一个文件夹。我该如何开始？
答案 0 :(得分：14)
如果您不需要PIL的其余部分，只需要PNG，JPEG和GIF的图像尺寸，那么这个小功能（BSD许可证）可以很好地完成工作：
http://code.google.com/p/bfg-pages/source/browse/trunk/pages/getimageinfo.py
import StringIO
import struct
def getImageInfo(data):
data = str(data)
size = len(data)
height = -1
width = -1
content_type = ''
# handle GIFs
if (size >= 10) and data[:6] in ('GIF87a', 'GIF89a'):
# Check to see if content_type is correct
content_type = 'image/gif'
w, h = struct.unpack("<HH", data[6:10])
width = int(w)
height = int(h)
# See PNG 2. Edition spec (http://www.w3.org/TR/PNG/)
# Bytes 0-7 are below, 4-byte chunk length, then 'IHDR'
# and finally the 4-byte width, height
elif ((size >= 24) and data.startswith('\211PNG\r\n\032\n')
and (data[12:16] == 'IHDR')):
content_type = 'image/png'
w, h = struct.unpack(">LL", data[16:24])
width = int(w)
height = int(h)
# Maybe this is for an older PNG version.
elif (size >= 16) and data.startswith('\211PNG\r\n\032\n'):
# Check to see if we have the right content type
content_type = 'image/png'
w, h = struct.unpack(">LL", data[8:16])
width = int(w)
height = int(h)
# handle JPEGs
elif (size >= 2) and data.startswith('\377\330'):
content_type = 'image/jpeg'
jpeg = StringIO.StringIO(data)
jpeg.read(2)
b = jpeg.read(1)
try:
while (b and ord(b) != 0xDA):
while (ord(b) != 0xFF): b = jpeg.read(1)
while (ord(b) == 0xFF): b = jpeg.read(1)
if (ord(b) >= 0xC0 and ord(b) <= 0xC3):
jpeg.read(3)
h, w = struct.unpack(">HH", jpeg.read(4))
break
else:
jpeg.read(int(struct.unpack(">H", jpeg.read(2))[0])-2)
b = jpeg.read(1)
width = int(w)
height = int(h)
except struct.error:
pass
except ValueError:
pass
return content_type, width, height
答案 1 :(得分：8)
一种常见的方法是使用PIL，即python成像库来获取尺寸：
from PIL import Image
import os.path
filename = os.path.join('path', 'to', 'image', 'file')
img = Image.open(filename)
print img.size
然后，您需要遍历目录中的文件，根据所需尺寸检查尺寸，并移动那些不匹配的文件。
答案 2 :(得分：6)
您可以使用Python Imaging Library（又名PIL）阅读图片标题并查询尺寸。
接近它的一种方法是自己编写一个带文件名并返回维度的函数（使用PIL）。然后使用os.path.walk函数遍历目录中的所有文件，应用此函数。收集结果，您可以构建映射字典filename -> dimensions，然后使用列表推导（请参阅itertools）过滤掉那些与所需大小不匹配的字典。
答案 3 :(得分：2)
这是一个可以满足您需求的脚本：
cl.get_platforms()答案 4 :(得分：0)
我对上面提供的答案非常满意，因为那些帮助我为这个问题写了另一个简单的答案。
由于上面的答案只有脚本，所以读者需要运行检查它们是否正常工作。所以我决定使用交互模式编程（来自Python shell）解决问题。
我想你会很清楚。我正在使用 Python 2.7.12 ，我已经安装了 Pillow 库来使用PIL来访问图像。我在当前目录中有很多jpg图像和1个png图像。
现在让我们转到Python shell。
>>> #Date of creation : 3 March 2017
>>> #Python version : 2.7.12
>>>
>>> import os #Importing os module
>>> import glob #Importing glob module to list the same type of image files like jpg/png(here)
>>>
>>> for extension in ["jpg", 'png']:
... print "List of all "+extension+" files in current directory:-"
... i = 1
... for imgfile in glob.glob("*."+extension):
... print i,") ",imgfile
... i += 1
... print "\n"
...
List of all jpg files in current directory:-
1 ) 002-tower-babel.jpg
2 ) 1454906.jpg
3 ) 69151278-great-hd-wallpapers.jpg
4 ) amazing-ancient-wallpaper.jpg
5 ) Ancient-Rome.jpg
6 ) babel_full.jpg
7 ) Cuba-is-wonderfull.jpg
8 ) Cute-Polar-Bear-Images-07775.jpg
9 ) Cute-Polar-Bear-Widescreen-Wallpapers-07781.jpg
10 ) Hard-work-without-a-lh.jpg
11 ) jpeg422jfif.jpg
12 ) moscow-park.jpg
13 ) moscow_city_night_winter_58404_1920x1080.jpg
14 ) Photo1569.jpg
15 ) Pineapple-HD-Photos-03691.jpg
16 ) Roman_forum_cropped.jpg
17 ) socrates.jpg
18 ) socrates_statement1.jpg
19 ) steve-jobs.jpg
20 ) The_Great_Wall_of_China_at_Jinshanling-edit.jpg
21 ) torenvanbabel_grt.jpg
22 ) tower_of_babel4.jpg
23 ) valckenborch_babel_1595_grt.jpg
24 ) Wall-of-China-17.jpg
List of all png files in current directory:-
1 ) gergo-hungary.png
>>> #So let's display all the resolutions with the filename
... from PIL import Image #Importing Python Imaging library(PIL)
>>> for extension in ["jpg", 'png']:
... i = 1
... for imgfile in glob.glob("*."+extension):
... img = Image.open(imgfile)
... print i,") ",imgfile,", resolution: ",img.size[0],"x",img.size[1]
... i += 1
... print "\n"
...
1 ) 002-tower-babel.jpg , resolution: 1024 x 768
2 ) 1454906.jpg , resolution: 1920 x 1080
3 ) 69151278-great-hd-wallpapers.jpg , resolution: 5120 x 2880
4 ) amazing-ancient-wallpaper.jpg , resolution: 1920 x 1080
5 ) Ancient-Rome.jpg , resolution: 1000 x 667
6 ) babel_full.jpg , resolution: 1464 x 1142
7 ) Cuba-is-wonderfull.jpg , resolution: 1366 x 768
8 ) Cute-Polar-Bear-Images-07775.jpg , resolution: 1600 x 1067
9 ) Cute-Polar-Bear-Widescreen-Wallpapers-07781.jpg , resolution: 2300 x 1610
10 ) Hard-work-without-a-lh.jpg , resolution: 650 x 346
11 ) jpeg422jfif.jpg , resolution: 2048 x 1536
12 ) moscow-park.jpg , resolution: 1920 x 1200
13 ) moscow_city_night_winter_58404_1920x1080.jpg , resolution: 1920 x 1080
14 ) Photo1569.jpg , resolution: 480 x 640
15 ) Pineapple-HD-Photos-03691.jpg , resolution: 2365 x 1774
16 ) Roman_forum_cropped.jpg , resolution: 4420 x 1572
17 ) socrates.jpg , resolution: 852 x 480
18 ) socrates_statement1.jpg , resolution: 1280 x 720
19 ) steve-jobs.jpg , resolution: 1920 x 1080
20 ) The_Great_Wall_of_China_at_Jinshanling-edit.jpg , resolution: 4288 x 2848
21 ) torenvanbabel_grt.jpg , resolution: 1100 x 805
22 ) tower_of_babel4.jpg , resolution: 1707 x 956
23 ) valckenborch_babel_1595_grt.jpg , resolution: 1100 x 748
24 ) Wall-of-China-17.jpg , resolution: 1920 x 1200
1 ) gergo-hungary.png , resolution: 1236 x 928
>>>
答案 5 :(得分：0)
您还可以使用cv2库检查图像的尺寸。
import cv2
# read image
img = cv2.imread('boarding_pass.png', cv2.IMREAD_UNCHANGED)
# get dimensions of image
dimensions = img.shape
# height, width, number of channels in image
height = img.shape[0]
width = img.shape[1]
channels = img.shape[2]
print('Image Dimension : ',dimensions)
print('Image Height : ',height)
print('Image Width : ',width)
print('Number of Channels : ',channels)
答案 6 :(得分：0)
如果您使用 ipython / jupyter notebook，这个功能就像一个魅力。方便的命令是 linux 终端中的 file 命令。你问值不值？这里：
def get_image_size_faster(file_dir, ext='png'):
"""
Function to retrieve image size without loading the image at all
params:
file_dir = path of the folder containing image files
dim_index = index of image dimensions in the `file $file_path` call output
For PNG : -3 # Downloads/test.png: PNG image data, 4032 x 3024, 8-bit/color RGB, non-interlaced
For JPEG/JPG : -2 # Downloads/test.jpg: JPEG image data,..., baseline, precision 8, 2252x1400, components 3
For GIF : -1 # Downloads/test.gif: GIF image data, version 89a, 498 x 373
"""
dim_index_map = {
'png' : -3,
'jpg' : -2,
'jpeg': -2,
'gif' : -1
}
dim_index = dim_index_map[ext]
files_regex = "{file_dir}/*.{ext}".format(file_dir=file_dir, ext=ext)
outputs = !file $files_regex
dims = [tuple(map(int, x.split(',')[dim_index].strip().split('x'))) for x in outputs]
return dims
可以使用 subprocess 包为该函数编写 Python 脚本替代方案，结果相同
答案 7 :(得分：-1)
import os
from PIL import Image
folder_images = "/tmp/photos"
size_images = dict()
for dirpath, _, filenames in os.walk(folder_images):
for path_image in filenames:
image = os.path.abspath(os.path.join(dirpath, path_image))
with Image.open(image) as img:
width, heigth = img.size
SIZE_IMAGES[path_image] = {'width': width, 'heigth': heigth}
print(size_images)
在folder_images中，您在箭头目录中显示图像。
size_images是一个具有图像大小的变量，采用这种格式。
Example
{'image_name.jpg' : {'width': 100, 'heigth': 100} }