Question

我正在创建一个标准的动态Web项目，包括一个Servlet，一个过滤请求和jsp页面的过滤器。我正在从welcome.jsp中获取书籍的数量，并根据计数我在add.jsp上填充输入框。我想过滤通过add.jsp传入的数据。当我通过Regex验证数据时，它显示我的错误。也是我的流程正确，即从开始FILTER - ＆gt;控制器 - ＆gt;过滤器 - ＆gt; PAGE等等???

错误： java.lang.NumberFormatException：null

完整跟踪就像：

HTTP Status 500 - java.lang.NumberFormatException: null

type Exception report

message java.lang.NumberFormatException: null

description The server encountered an internal error that prevented it from fulfilling this request.

exception

org.apache.jasper.JasperException: java.lang.NumberFormatException: null
    org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:549)
    org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:470)
    org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
    org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
    com.filter.RequestFilter.doFilter(RequestFilter.java:107)

root cause

java.lang.NumberFormatException: null
    java.lang.Integer.parseInt(Unknown Source)
    java.lang.Integer.parseInt(Unknown Source)
    org.apache.jsp.WEB_002dINF.add_jsp._jspService(add_jsp.java:139)
    org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
    org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)
    org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
    org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
    com.filter.RequestFilter.doFilter(RequestFilter.java:107)

显示的代码是：

public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
    // TODO Auto-generated method stub
    // place your code here
    boolean flag = true;
    HttpServletRequest httpServletRequest = (HttpServletRequest) request;
    HttpServletResponse httpResponse = (HttpServletResponse) response;
    httpServletRequest.getServletPath();
    System.out.println(httpServletRequest.getServletPath());


    String address = InetAddress.getLocalHost().getHostAddress();
    System.out.println(address); 


    // For the first time (Welcome page) i will be 0 so that it will perform first if

    if(i == 0)
    {
        System.out.println(i);
        if(verify(address))
        {
            chain.doFilter(request, response);
            i++;
        }

        else
        {
            RequestDispatcher requestDispatcher = httpServletRequest.getServletContext().getRequestDispatcher("/WEB-INF/forbidden.jsp");
            requestDispatcher.forward(request, response);
            return;
        }

    }

    // For the second time (Controller) i will be 1 so that it will perform first if


    else if(i == 1)
    {
        System.out.println(i);
        i++;
        System.out.println("after ++"+i);
        chain.doFilter(request, response);
    }

    // For the second time (add page) i will be 2 so that it will perform first if


    else if(i == 2)
    {

        if(specialChara(httpServletRequest))
            {
                System.out.println(i);
                System.out.println("done");
                i++;
                chain.doFilter(request, response);
            }

            else
            {
                System.out.println(i);
                flag = false;
                System.out.println(""+httpServletRequest.toString()+ "\n"+httpResponse.toString());
                RequestDispatcher requestDispatcher = httpServletRequest.getServletContext().getRequestDispatcher("/WEB-INF/add.jsp");
                requestDispatcher.forward(request, response);

            }
    }

    // For the third time (Controller) i will be 2 so that it will perform first if

    else if(i == 3)
    {
        System.out.println(i);
        i++;
        chain.doFilter(request, response);
        i = 0;
    }

它在循环中的forward（）行给出错误，其中i == 2。可能是什么问题？

add.jsp的

链接是https://docs.google.com/document/d/1fOzymYvlLXS577DrSrznRoeBnI7_hMmuqzFoK02xKoU/edit?usp=sharing

Answer 1

从堆栈跟踪看来，问题不在于您的java类，而在于您的JSP。我猜是在行

int no = Integer.parseInt(request.getParameter("no"));

似乎没有null。你最好还是使用和其他条件标签，而不是在JSP中使用scriptlet。

HTTP状态500 - java.lang.NumberFormatException：null

1 个答案: