Question

我有一个带有POST提交按钮的表单。我希望在提交表单和form.is_valid（）。

时链接到新页面

在视图或模板中创建链接是否更好？怎么做？

view.py：

from django.shortcuts import render_to_response
from ezmapping.models import *
from django.forms.models import modelformset_factory

def setName(request):
    ezAppFormSet = modelformset_factory(ezApp, extra=1, fields=('name'))
    formset = ezAppFormSet(queryset=ezApp.objects.none())
    if request.method == 'POST':
        formset = ezAppFormSet(request.POST, request.FILES)
        if formset.is_valid():
            formset.save()
    return render_to_response("project/manage_new.html", {'formset': formset, 'title': "New"}, context_instance=RequestContext(request))

template.html

 {% extends "basemap.html" %}
 {% block content %}
 <table border="1">
   <tr>
   <td>
    <h1>Define new App options</h1>
    {% if formset.errors %}
        <p style="color: red;">
            Please correct the error{{ formset.errors|pluralize }} below.
        </p>
    {% endif %}
    <form method="post" action="." encrypt="multipart/form-data">{% csrf_token %}
            {{ formset.as_p }}
        <input type="submit" value="Submit">
    </form>
</td>
</tr>
</table>
{% endblock %}

Answer 1

您可以在视图中使用HttpResponseRedirect（），如下所示：

from django.shortcuts import render_to_response
from ezmapping.models import *
from django.forms.models import modelformset_factory

def setName(request):
    ezAppFormSet = modelformset_factory(ezApp, extra=1, fields=('name'))
    formset = ezAppFormSet(queryset=ezApp.objects.none())
    if request.method == 'POST':
        formset = ezAppFormSet(request.POST, request.FILES)
        if formset.is_valid():
            formset.save()
            next_link = u"/next/"
            return HttpResponseRedirect(next_link)

    return render_to_response("project/manage_new.html", {'formset': formset, 'title': "New"}, context_instance=RequestContext(request))

Answer 2

不确定。只需在request.method == 'POST'的条件内返回render_to_response，或者可选地，只需将上下文和模板设置为变量，以便将其转换为render_to_response：

意译：

def foo(request):
    template = 'template1.html'
    # form and formsets here set into `context` as a dictionary

    if request.method == 'POST':
        template = 'template2.html'

    return render_to_response(template, context)

[编辑]

当我重新阅读您的问题时，如果您希望在表单有效时重定向到其他视图，请改为返回HttpResponseRedirect。

Answer 3

如果我理解你的问题。

您的观点：

from django.shortcuts import render_to_response
from ezmapping.models import *
from django.forms.models import modelformset_factory

def setName(request):
    ezAppFormSet = modelformset_factory(ezApp, extra=1, fields=('name'))
    formset = ezAppFormSet(queryset=ezApp.objects.none())
    if request.method == 'POST':
        formset = ezAppFormSet(request.POST, request.FILES)
        if formset.is_valid():
            formset.save()
            submit_link = True # 2*
        else:
            submit_link = False
    return render_to_response("project/manage_new.html", {'submit_link': submit_link, 'formset': formset, 'title': "New"}, context_instance=RequestContext(request))

您的模板：

{% extends "basemap.html" %}
 {% block content %}
 <table border="1">
   <tr>
   <td>
    <h1>Define new App options</h1>
    {% if formset.errors %}
        <p style="color: red;">
            Please correct the error{{ formset.errors|pluralize }} below.
        </p>
    {% endif %}
    <form method="post" action="." encrypt="multipart/form-data">{% csrf_token %}
            {{ formset.as_p }}
        <input type="submit" value="Submit">
    </form>

    {% if submit_link %} 
      <a href='/next/'>Data is saved, let's continue.</a>
    {% endif %}
</td>
</tr>
</table>
{% endblock %}

<强>更新

是的，如果您想重定向（而不是显示下一个链接），请执行以下操作：

from django.shortcuts import redirect
...
return redirect( 'you-url' )

而不是2 *。

Django - 提交链接

3 个答案: