为什么SwingWorker会意外停止?

时间:2013-02-15 18:05:49

标签: java multithreading swing concurrency swingworker

我想用SwingWorker尝试一些想法,因为我没有太多使用它。相反,我遇到了一个问题,我无法弄清楚出了什么问题。

这是一个简短的SSCCE来证明这个问题(我知道这里的人就像SSCCE一样):

import javax.swing.SwingUtilities;
import javax.swing.SwingWorker;

public class SwingWorkerTest
{
    public static void main (String[] args)
    {
        SwingUtilities.invokeLater (new Runnable ()
        {
            @Override
            public void run ()
            {
                new MySwingWorker (500).execute ();
                new MySwingWorker (900).execute ();
                new MySwingWorker (1200).execute ();
            }
        });
    }
}

class MySwingWorker extends SwingWorker<Void, Void>
{
    private int ms;

    public MySwingWorker (int ms)
    {
        this.ms = ms;
    }

    @Override
    protected Void doInBackground()
    {
        Thread t = Thread.currentThread ();

        for (int i = 0; i < 50; i++)
        {
            try
            {
                Thread.sleep (ms);
            }
            catch (InterruptedException e)
            {
                e.printStackTrace ();
            }

            System.out.println ("I am thread with " + ms + " sleep in iteration " + i + ": " + t.getName () + " (" + t.getId () + ")");
        }

        return null;
    }
}

所以我的程序应该创建3个SwingWorkers,在屏幕上打印一行,然后睡眠指定的毫秒数,然后再次打印该行并再次睡眠等。我在Swing的线程中创建了SwingWorker,因为否则他们甚至都不会开始。

所以预期的输出是:

I am thread with 500 sleep in iteration 0: SwingWorker-pool-1-thread-1 (15)
I am thread with 900 sleep in iteration 0: SwingWorker-pool-1-thread-2 (16)
I am thread with 500 sleep in iteration 1: SwingWorker-pool-1-thread-1 (15)
I am thread with 1200 sleep in iteration 0: SwingWorker-pool-1-thread-3 (17)
I am thread with 500 sleep in iteration 2: SwingWorker-pool-1-thread-1 (15)
I am thread with 900 sleep in iteration 1: SwingWorker-pool-1-thread-2 (16)
I am thread with 500 sleep in iteration 3: SwingWorker-pool-1-thread-1 (15)
I am thread with 1200 sleep in iteration 1: SwingWorker-pool-1-thread-3 (17)
I am thread with 500 sleep in iteration 4: SwingWorker-pool-1-thread-1 (15)
I am thread with 900 sleep in iteration 2: SwingWorker-pool-1-thread-2 (16)
I am thread with 500 sleep in iteration 5: SwingWorker-pool-1-thread-1 (15)
I am thread with 500 sleep in iteration 6: SwingWorker-pool-1-thread-1 (15)
I am thread with 900 sleep in iteration 3: SwingWorker-pool-1-thread-2 (16)
I am thread with 1200 sleep in iteration 2: SwingWorker-pool-1-thread-3 (17)
I am thread with 500 sleep in iteration 7: SwingWorker-pool-1-thread-1 (15)
.............

等等,共计150行(3名工人x 50次迭代)

相反,我得到的输出是:

I am thread with 500 sleep in iteration 0: SwingWorker-pool-1-thread-1 (15)
I am thread with 900 sleep in iteration 0: SwingWorker-pool-1-thread-2 (16)
I am thread with 500 sleep in iteration 1: SwingWorker-pool-1-thread-1 (15)

就是这样。只需3行。在此之后程序退出。 try catch块之外的任何地方都没有堆栈跟踪。

1)。 1200毫秒睡觉的工人在哪里?实际上,如果我用1000毫秒替换1200毫秒,那么这个工作者也打印1行......是的,只有一行。奇怪的...

2)。为什么工人会停下来? (我没有得到150行的东西)

我在Windows 7 64位上使用 JRE 7 Update 11运行此程序。

PS:我很确定在这个版本的JRE中修复了the bug mentioned here,因为我确实得到了2个不同的值(15和16)作为在控制台上打印的线程ID。这是我怀疑的第一件事。

4 个答案:

答案 0 :(得分:9)

我相信你需要显示一个可视化的Swing顶级窗口,以保持Swing事件线程的活动。否则,程序将因缺少非守护程序线程而关闭。

修改
要证明SwingWorker线程是一个守护程序线程,只需添加一行代码来测试它:

System.out.println("I am thread with " + ms + " sleep in iteration "
   + i + ": " + t.getName() + " (" + t.getId() + ")");

// **** added
System.out.println("Daemon?: " + Thread.currentThread().isDaemon()); 

答案 1 :(得分:9)

如果查看SwingWorker类源代码(Java SE 7)的第771行:

thread.setDaemon(true);

您将看到SwingWorker在守护程序线程中执行,而在Java中,如果所有非守护程序线程都已完成,JVM将被终止。

答案 2 :(得分:4)

如前所述,您可以使用UI来保持线程活跃。

或者,您可以使用SwingWorker#get(或阻止主线程终止的任何内容)等待线程完成。通过这样做,您将获得预期的输出。这是经过修改的代码,可以满足您的需求。

import javax.swing.SwingUtilities;
import javax.swing.SwingWorker;
import java.util.concurrent.ExecutionException;

public class SwingWorkerTest
{
    public static void main (String[] args)
    {
        final MySwingWorker w1 = new MySwingWorker (500),
         w2 = new MySwingWorker (900),
         w3 = new MySwingWorker (1200);
        SwingUtilities.invokeLater (new Runnable ()
        {
            @Override
            public void run ()
            {
                w1.execute ();
                w2.execute ();
                w3.execute ();
            }
        });

        try{
            // you can replace the code in this block
            // by anything that keeps the program from 
            // terminating before the threads/SwingWorkers.
            w1.get();
            w2.get(); 
            w3.get(); 
        }catch(InterruptedException e){
            System.err.println("InterruptedException occured");
        }catch(ExecutionException e){
            System.err.println("InterruptedException occured");
        }

    }
}

class MySwingWorker extends SwingWorker<Void, Void>
{
    private int ms;

    public MySwingWorker (int ms)
    {
        this.ms = ms;
    }

    @Override
    protected Void doInBackground()
    {
        Thread t = Thread.currentThread ();

        for (int i = 0; i < 50; i++)
        {
            try
            {
                Thread.sleep (ms);
            }
            catch (InterruptedException e)
            {
                e.printStackTrace ();
            }

            System.out.println ("I am thread with " + ms + " sleep in iteration " + i + ": " + t.getName () + " (" + t.getId () + ")");
        }

        return null;
    }
}

答案 3 :(得分:3)

您是否尝试过创建任何用户界面?或者在main的末尾放置new Object().wait();之类的内容,以防止主线程退出?

我不是完全确定这是这种情况,但是没有任何实际的UI显示,我很确定swing工作者只是另一个线程,并且你没有配置任何守护程序线程,所以main启动它们,主要完成,并且进程退出?