所以我尝试使用this gem和simple_form实现多个自动完成功能,但是收到错误。
我试过了:
<%= f.input_field :neighborhood_id, collection: Neighborhood.order(:name), :url => autocomplete_neighborhood_name_searches_path, :as => :autocomplete, 'data-delimiter' => ',', :multiple => true, :class => "span8" %>
这是我得到的错误:
undefined method `to_i' for ["Alley Park, Madison"]:Array
在我的参数中,它是在neighborhood_id
发送的:
"search"=>{"neighborhood_id"=>["Alley Park, Madison"],
所以它甚至没有使用这些值的ID。
有没有人有任何想法?
修改1:
在回答@jvnill的问题时,我并没有明确地在控制器中对params[:search]
做任何事情。搜索会创建新记录,并正在搜索listings
。
在我的搜索控制器中,create
操作,我只是这样做:
@search = Search.create!(params[:search])
然后我的search.rb
(即搜索模型)有这个:
def listings
@listings ||= find_listings
end
private
def find_listings
key = "%#{keywords}%"
listings = Listing.order(:headline)
listings = listings.includes(:neighborhood).where("listings.headline like ? or neighborhoods.name like ?", key, key) if keywords.present?
listings = listings.where(neighborhood_id: neighborhood_id) if neighborhood_id.present?
#truncated for brevity
listings
end
答案 0 :(得分:1)
首先,如果表单返回id而不是邻域名称,这将更容易。我还没有使用过宝石,所以我不熟悉它是如何工作的。阅读自述文件说它会返回ID但我不知道你为什么只得到名字。我相信一旦你弄清楚如何返回id,你就可以改变下面的代码来适应这个。
您需要在邻域和搜索之间创建连接表。我们称之为search_neighborhoods。
rails g model search_neighborhood neighborhood_id:integer search_id:integer
# dont forget to add indexes in the migration
之后,您需要设置模型。
# search.rb
has_many :search_neighborhoods
has_many :neighborhoods, through: :search_neighborhoods
# search_neighborhood.rb
belongs_to :search
belongs_to :neighborhood
# neighborhood.rb
has_many :search_neighborhoods
has_many :searches, through: :search_neighborhoods
现在我们已经设置了关联,我们需要设置setter和属性
# search.rb
attr_accessible :neighborhood_names
# this will return a list of neighborhood names which is usefull with prepopulating
def neighborhood_names
neighborhoods.map(&:name).join(',')
end
# we will use this to find the ids of the neighborhoods given their names
# this will be called when you call create!
def neighborhood_names=(names)
names.split(',').each do |name|
next if name.blank?
if neighborhood = Neighborhood.find_by_name(name)
search_neighborhoods.build neighborhood_id: neighborhood.id
end
end
end
# view
# you need to change your autocomplete to use the getter method
<%= f.input :neighborhood_names, url: autocomplete_neighborhood_name_searches_path, as: :autocomplete, input_html: { data: { delimiter: ',', multiple: true, class: "span8" } %>
最后但并非最不重要的是更新find_listings
def find_listings
key = "%#{keywords}%"
listings = Listing.order(:headline).includes(:neighborhood)
if keywords.present?
listings = listings.where("listings.headline LIKE :key OR neighborhoods.name LIKE :key", { key: "#{keywords}")
end
if neighborhoods.exists?
listings = listings.where(neighborhood_id: neighborhood_ids)
end
listings
end
就是这样:))
更新:使用f.input_field
# view
<%= f.input_field :neighborhood_names, url: autocomplete_neighborhood_name_searches_path, as: :autocomplete, data: { delimiter: ',' }, multiple: true, class: "span8" %>
# model
# we need to put [0] because it returns an array with a single element containing
# the string of comma separated neighborhoods
def neighborhood_names=(names)
names[0].split(',').each do |name|
next if name.blank?
if neighborhood = Neighborhood.find_by_name(name)
search_neighborhoods.build neighborhood_id: neighborhood.id
end
end
end
答案 1 :(得分:0)
您的问题是如何从邻近模型中收集值
Neighborhood.order(:name)
将返回一个名称数组,您还需要收集id,但只显示名称 使用收集并传递一个块,我相信这可能是你的伙伴
Neighborhood.collect {|n| [n.name, n.id]}
如果您希望恢复该功能,则在Neighborhood类上声明一个范围以按名称对其进行排序,因为该行为也无论如何都属于模型。
编辑&gt; 要将范围/类方法添加到邻域模型,您通常会像这样做
scope :desc, where("name DESC")
你可以写一些像:
Neighborhood.desc.all
将返回一个数组,从而允许.collect,但还有其他方法可以获得select选项识别的那些name和id属性。