所以这就是我在dev(SQLite)环境中完美运行的原因:
key = "%#{keywords}%"
listings = Listing.order(:headline)
listings = listings.includes(:neighborhood).where("headline like ? or neighborhoods.name like ?", key, key) if keywords.present?
但是,当我在Heroku上尝试类似的东西时,我会遇到一些错误:
listings = listings.includes(:neighborhood).where("headline like ? or neighborhoods.name like ?", key, key)
ActiveRecord::ConfigurationError: Association named 'neighborhoods' was not found; perhaps you misspelled it?
我也试过以下&得到了相应的错误:
> listings = Listing.includes(:neighborhood).where("headline like :keywords or neighborhood.name like :keywords", :keywords => "%#{keywords}%")
SQL (3.1ms) SELECT "listings"."id" AS t0_r0, "listings"."listing_category_id" AS t0_r1, "listings"."listing_type_id" AS t0_r2, "listings"."user_id" AS t0_r3, "listings"."boro_id" AS t0_r4, "listings"."neighborhood_id" AS t0_r5, "listings"."building_id" AS t0_r6, "listings"."term_id" AS t0_r7, "listings"."headline" AS t0_r8, "listings"."property_type_id" AS t0_r9, "listings"."unit_num" AS t0_r10, "listings"."common_charges" AS t0_r11, "listings"."taxes" AS t0_r12, "listings"."maintenance" AS t0_r13, "listings"."num_bedrooms" AS t0_r14, "listings"."num_bathrooms" AS t0_r15, "listings"."square_footage" AS t0_r16, "listings"."list_square_footage" AS t0_r17, "listings"."description" AS t0_r18, "listings"."condition_id" AS t0_r19, "listings"."pet_policy_id" AS t0_r20, "listings"."exposure_id" AS t0_r21, "listings"."floor_plan" AS t0_r22, "listings"."photo" AS t0_r23, "listings"."security" AS t0_r24, "listings"."coop_deductible" AS t0_r25, "listings"."flip_tax" AS t0_r26, "listings"."house_families" AS t0_r27, "listings"."house_extensions" AS t0_r28, "listings"."house_stories" AS t0_r29, "listings"."house_units" AS t0_r30, "listings"."created_at" AS t0_r31, "listings"."updated_at" AS t0_r32, "listings"."price" AS t0_r33, "neighborhoods"."id" AS t1_r0, "neighborhoods"."name" AS t1_r1, "neighborhoods"."created_at" AS t1_r2, "neighborhoods"."updated_at" AS t1_r3, "neighborhoods"."boro_id" AS t1_r4 FROM "listings" LEFT OUTER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id" WHERE (headline like '%prospect heights%' or neighborhood.name like '%prospect heights%')
ActiveRecord::StatementInvalid: PG::Error: ERROR: missing FROM-clause entry for table "neighborhood"
LINE 1: ..._id" WHERE (headline like '%prospect heights%' or neighborho...
^
: SELECT "listings"."id" AS t0_r0, "listings"."listing_category_id" AS t0_r1, "listings"."listing_type_id" AS t0_r2, "listings"."user_id" AS t0_r3, "listings"."boro_id" AS t0_r4, "listings"."neighborhood_id" AS t0_r5, "listings"."building_id" AS t0_r6, "listings"."term_id" AS t0_r7, "listings"."headline" AS t0_r8, "listings"."property_type_id" AS t0_r9, "listings"."unit_num" AS t0_r10, "listings"."common_charges" AS t0_r11, "listings"."taxes" AS t0_r12, "listings"."maintenance" AS t0_r13, "listings"."num_bedrooms" AS t0_r14, "listings"."num_bathrooms" AS t0_r15, "listings"."square_footage" AS t0_r16, "listings"."list_square_footage" AS t0_r17, "listings"."description" AS t0_r18, "listings"."condition_id" AS t0_r19, "listings"."pet_policy_id" AS t0_r20, "listings"."exposure_id" AS t0_r21, "listings"."floor_plan" AS t0_r22, "listings"."photo" AS t0_r23, "listings"."security" AS t0_r24, "listings"."coop_deductible" AS t0_r25, "listings"."flip_tax" AS t0_r26, "listings"."house_families" AS t0_r27, "listings"."house_extensions" AS t0_r28, "listings"."house_stories" AS t0_r29, "listings"."house_units" AS t0_r30, "listings"."created_at" AS t0_r31, "listings"."updated_at" AS t0_r32, "listings"."price" AS t0_r33, "neighborhoods"."id" AS t1_r0, "neighborhoods"."name" AS t1_r1, "neighborhoods"."created_at" AS t1_r2, "neighborhoods"."updated_at" AS t1_r3, "neighborhoods"."boro_id" AS t1_r4 FROM "listings" LEFT OUTER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id" WHERE (headline like '%prospect heights%' or neighborhood.name like '%prospect heights%')
我也尝试过并收到以下错误:
0> listings = Listing.joins(:neighborhood).where("headline like :keywords or neighborhood.name like :keywords", :keywords => "%#{keywords}%")
Listing Load (2.7ms) SELECT "listings".* FROM "listings" INNER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id" WHERE (headline like '%prospect heights%' or neighborhood.name like '%prospect heights%')
ActiveRecord::StatementInvalid: PG::Error: ERROR: missing FROM-clause entry for table "neighborhood"
LINE 1: ..._id" WHERE (headline like '%prospect heights%' or neighborho...
^
: SELECT "listings".* FROM "listings" INNER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id" WHERE (headline like '%prospect heights%' or neighborhood.name like '%prospect heights%')
思想?
感谢。
修改1:
列表belongs_to neighborhood
和邻居has_many listings
。
编辑2:
提取了一个SQL语句并通过psql
运行,结果如下:
SELECT "listings".* FROM "listings" INNER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id" WHERE (headline like '%prospect heights%' or neighborhood.name like '%prospect heights%');
ERROR: missing FROM-clause entry for table "neighborhood"
LINE 1: ..._id" WHERE (headline like '%prospect heights%' or neighborho...
答案 0 :(得分:1)
尝试以下方法:
listings = Listing.includes(:neighborhood).where("listings.headline like :keywords or neighborhoods.name like :keywords", :keywords => "%#{keywords}%")
我认为它应该调用listings.headline
而不是headline
SELECT "listings".* FROM "listings" INNER JOIN "neighborhoods"
ON "neighborhoods"."id" = "listings"."neighborhood_id"
WHERE (
headline like '%prospect heights%' #I mean here
or neighborhood.name like '%prospect heights%') #also here, should be neighborhoods.name
编辑 - 你知道SQLite和PostgreSQL之间有什么区别吗?我遇到了类似的problem。我想你想要ILIKE而不是LIKE:
listings = Listing.includes(:neighborhood).where("listings.headline ilike :keywords or neighborhoods.name ilike :keywords", :keywords => "%#{keywords}%")
答案 1 :(得分:1)
重新格式化的查询:
SELECT "listings"."id" AS t0_r0,
"listings"."listing_category_id" AS t0_r1,
"listings"."listing_type_id" AS t0_r2,
"listings"."user_id" AS t0_r3,
"listings"."boro_id" AS t0_r4,
"listings"."neighborhood_id" AS t0_r5,
"listings"."building_id" AS t0_r6,
"listings"."term_id" AS t0_r7,
"listings"."headline" AS t0_r8,
"listings"."property_type_id" AS t0_r9,
"listings"."unit_num" AS t0_r10,
"listings"."common_charges" AS t0_r11,
"listings"."taxes" AS t0_r12,
"listings"."maintenance" AS t0_r13,
"listings"."num_bedrooms" AS t0_r14,
"listings"."num_bathrooms" AS t0_r15,
"listings"."square_footage" AS t0_r16,
"listings"."list_square_footage" AS t0_r17,
"listings"."description" AS t0_r18,
"listings"."condition_id" AS t0_r19,
"listings"."pet_policy_id" AS t0_r20,
"listings"."exposure_id" AS t0_r21,
"listings"."floor_plan" AS t0_r22,
"listings"."photo" AS t0_r23,
"listings"."security" AS t0_r24,
"listings"."coop_deductible" AS t0_r25,
"listings"."flip_tax" AS t0_r26,
"listings"."house_families" AS t0_r27,
"listings"."house_extensions" AS t0_r28,
"listings"."house_stories" AS t0_r29,
"listings"."house_units" AS t0_r30,
"listings"."created_at" AS t0_r31,
"listings"."updated_at" AS t0_r32,
"listings"."price" AS t0_r33,
"neighborhoods"."id" AS t1_r0,
"neighborhoods"."name" AS t1_r1,
"neighborhoods"."created_at" AS t1_r2,
"neighborhoods"."updated_at" AS t1_r3,
"neighborhoods"."boro_id" AS t1_r4
FROM "listings"
LEFT OUTER JOIN "neighborhoods" ON "neighborhoods"."id" = "listings"."neighborhood_id"
WHERE (headline LIKE '%prospect heights%'
OR neighborhood.name LIKE '%prospect heights%');
问题似乎很明显。你包括表“邻里”,但后来试图使用“邻居”。 如何在RoR中解决这个问题 - 不知道,但也许足以让你指出正确的方向。
答案 2 :(得分:1)
诊断这一点的最佳方法是确保您的开发和生产环境尽可能匹配,并实际在本地运行PostgreSQL。不可避免地,您会遇到难以调试的SQLite和PostgreSQL之间的不一致,或者在您推送代码时会让您感到惊讶。
如果您使用的是Mac,Heroku Postgres有一个独立的应用程序,您可以在没有配置的情况下下载和使用:http://postgresapp.com/