我是Spring的新手,我正在开发一个虚拟银行交易项目。到目前为止,我已经创建了一个欢迎页面,将我链接到我可以执行存款或取消交易的页面。数据库和一切正常。而且,我有一个表格,显示有4个属性(id,name,acctNo,balance)的客户列表。 id链接到下一页,我只想显示有关此客户的信息。我怎样才能做到这一点。
Dispatcher-Servlet.xml是:
<?xml version="1.0" encoding="UTF-8"?>
<beans
xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"
xmlns:p="http://www.springframework.org/schema/p">
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/jsp/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
<bean id="urlMapping"
class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="interceptors">
<list>
<ref local="localeChangeInterceptor"/>
</list>
</property>
<property name="urlMap">
<map>
<entry key="/login.html">
<ref bean="userloginController"/>
</entry>
</map>
</property>
</bean>
<!-- I tried adding this bean but noe luck, not sure where to use this id to map this bean -->
<bean id="showindividualCustomer" class="com.showCustomerController">s
<property name="successView"> <value>ViewCustomer</value></property>
</bean>
<bean id="userloginController" class="com.UserLoginFormController">
<property name="sessionForm"><value>false</value></property>
<property name="commandName"><value>userLogin</value></property>
<property name="commandClass"><value>com.UserLogin</value></property>
<property name="formView"><value>userLogin</value></property>
<property name="successView"><value>showCustomer</value></property>
</bean>
<bean id="localeChangeInterceptor" class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor">
<property name="paramName" value="hl"/>
</bean>
<bean id="localeResolver" class="org.springframework.web.servlet.i18n.SessionLocaleResolver"/>
</beans>
bean = showindividualcustomer的控制器是:
public class showCustomerController extends SimpleFormController{
protected ModelAndView onSubmit(Object obj) throws ServletException{
return new ModelAndView("ViewCustomer");//name of the jsp page inside WEB-INF/jsp
}
}
谢谢!!!
答案 0 :(得分:2)
我实际上建议充分利用spring 3,查看你的代码我假设你正在看一个spring 2教程。
使用弹簧2.5.6或弹簧3. *你可以这样做:
@RequestMapping(value="/customer/{id}")
public String showCustomerInformation(@PathVariable String id, HttpServletRequest request){
//your logic to get the customer information and pass it on
return "customerInformation";
}
一些参考文献: http://tech-read.com/2011/10/31/spring-3-mvc-annotations/ http://static.springsource.org/spring/docs/3.2.x/spring-framework-reference/html/mvc.html#mvc-ann-requestparam
编辑: 将您的方法签名更改为:
onSubmit(HttpServletRequest request, Object command) throws ServletException
只需使用:
request.getParameter("id")