所以我注意到当你取消引用只有1维的二维数组时,postgres(9.0)不喜欢它。这是一个有趣的例子
WITH my_table(arr) AS ( VALUES (ARRAY[[10,11],[20,21]]) )
SELECT arr[2][1] AS good, arr[1] AS bad FROM my_table;
good | bad
------+-----
20 |
(1 row)
正如您所看到的,当您未指定第二个维度时,它会返回null
。理想情况下,我希望它返回内部数组{10,11}
。所以为了解决这个问题,我写了这个函数
CREATE OR REPLACE FUNCTION deref_2d(orig_arr numeric[][], inner_arr int)
RETURNS numeric[] AS $$
DECLARE
index int;
len int;
return_arr numeric[];
BEGIN
len := array_upper(orig_arr,2);
FOR index IN 1 .. len LOOP
return_arr[index] := orig_arr[inner_arr][index];
END LOOP;
RETURN return_arr;
END
$$ LANGUAGE plpgsql;
现在我可以写:
WITH my_table(arr) AS ( VALUES (ARRAY[[10,11],[20,21]]) )
SELECT deref_2d(arr,1) FROM my_table;
deref_2d
----------
{10,11}
但是有很多关于这一点的事情让我对我的解决方案感到不安。有更好的方法吗?
答案 0 :(得分:3)
在你把它写下来之前考虑一下这个西方人的全部演员:
WITH tbl(arr) AS (SELECT (ARRAY[[10,11],[20,21]]))
SELECT arr[2][1] AS the_good
,arr[1] AS the_bad
,arr[1:1] AS the_ugly -- first slice of 2D-array
,arr[1][1:2] AS the_ugly_twin -- 2D-array with elements 1 & 2 of 1st slice
,ARRAY((SELECT unnest(arr[1:1]))) AS the_righteous -- 1D-array of 1st slice
FROM tbl;
->sqlfiddle有更多例子。