Question

我有两个列表框，我正在尝试将列表1中的项目添加到列表2，然后能够一次从列表2中删除多个项目。请注意，列表1保持停滞（这应该是这样的。）

我有正确的添加项目：

'Add the selected items to List 2
Dim i As Integer

If lst1.ItemsSelected.Count > 0 Then
    i = 0
    While i < lst1.ListCount
        If lst1.Selected(i) Then
            lst2.AddItem (lst1.ItemData(i) & ";" & lst1.Column(1, i) & ";")
            lst1.Selected(i) = False
        End If
        i = i + 1
    Wend
End If

但是，当我尝试以类似的方式从列表2中删除项目时，它只会将第一个选定的项目识别为已选择，并跳过我选择的其他项目。这就是问题。这是我的代码：

'Remove the selected items from List 2
Dim i As Integer

If lst2.ItemsSelected.Count > 0 Then
    i = lst2.ListCount - 1
    While i >= 0
       If lst2.Selected(i) Then
           lst2.RemoveItem (i)
           lst2.Selected(i) = False
       End If
        i = i - 1
    Wend
End If

如何才能使其正常工作？

Answer 1

据我所知，只要删除一个项目，所有项目都会被取消选中，所以：

Dim itm As Variant
Dim srem As String
Dim asrem As Variant

    For Each itm In lst2.ItemsSelected
        srem = srem & "," & itm
    Next

    asrem = Split(Mid(srem, 2), ",")
    For i = UBound(asrem) To 0 Step -1
        lst2.RemoveItem lst2.ItemData(asrem(i))
    Next

另请注意，这是Access，您正在处理值列表，因此行源文本上的替换也可以。

Answer 2

尝试使用for / next循环而不是While？

像PPT / XLS这样的东西在我认为的Access中应该类似。

For i = lst2.ListCount - 1 to 0 step -1
    If lst2.Selected(i) = True Then
        lst2.RemoveItem(i)
    End If
Next

Answer 3

与@Fionnuala相同的概念，但我使用的集合通常更灵活：

Dim i As Integer
Dim listColl As Collection
Dim Item As Variant

Set listColl = New Collection
With Me.listAvailable
    ' Add Selected Items to Collection (MultiSelect Listbox)
     For i = 0 To .ListCount - 1
        If .Selected(i) Then
            listColl.Add .ItemData(i)
        End If
    Next i
End With

For Each Item In listColl
    Me.listSelected.AddItem Item
    Me.listAvailable.RemoveItem Item
Next Item

Answer 4

我使用了此代码，效果很好

Dim ArraySlctd() As Variant  'this Arry is to save what row is selected because when remove any row all selected are getting false
ReDim ArraySlctd(0 To Me.List1.ListCount - 1)
For lp = 0 To Me.List1.ListCount - 1 '
ArraySlctd(lp) = Me.List1.Selected(lp) 'work in the same range as the selected property
Next lp

现在简单易用

For lp = 0 To Me.List1.ListCount - 1
If ArraySlctd(lp) = True Then
'Remove Or Change(by remove and AddIten with the same Index)
End If

Next lp

删除列表框中的多个选定项目 - 仅识别第一个选择的代码

4 个答案: