Question

我需要在相同项目编号的数据透视表项目数据中对日期进行排序

该项目如下所示：

"Project nr"   "Task"                "Task deadline"  "Task Type Production"
123             pack                  1 april 2013    Pack
123             Leave production      3 april 2013    Leave Production
123             Flight date           9 april 2013    Flight Date

“任务类型生产”用于确保字段内容始终一致我只能在数据透视表中创建一列。有没有办法在3列中显示信息它看起来像这样：

Project nr ;  Pack   ;  leave production ; flightdate   


SELECT  [TaskDeadline] AS Packed
FROM         MSP_EpmTask_UserView where  [Task Type Production] = 'Packed'
SELECT  [TaskDeadline] AS LeaveProduction
FROM         MSP_EpmTask_UserView where  [Task Type Production] =  'Leave Production' 
SELECT  [TaskDeadline] AS FlightDate
FROM         MSP_EpmTask_UserView where  [Task Type Production] =  'Flight Date'

由于安

Answer 1

这可以使用聚合函数和CASE表达式轻松完成：

select  [Project nr],
    MAX(case when [Task Type Production] = 'Pack' then [Task deadline] end) as Pack,
    MAX(case when [Task Type Production] = 'Leave Production' then [Task deadline] end) as [Leave Production],
    MAX(case when [Task Type Production] = 'Flight Date' then [Task deadline] end) as [Flight Date]
from MSP_EpmTask_UserView 
group by    [Project nr]

请参阅SQL Fiddle with Demo

如果要在SQL Server中使用PIVOT函数，则查询将为：

select *
from
(
  select [Project nr],[Task deadline], [Task Type Production]
  from MSP_EpmTask_UserView 
) src
pivot
(
  max([Task deadline])
  for [Task Type Production] in ([Pack], [Leave Production],
                                 [Flight Date])
) piv

请参阅SQL Fiddle with Demo。

最后，可以使用表的多个连接来完成此操作：

select t1.[Project nr],
  t1.[Task deadline] pack,
  t2.[Task deadline] [Leave Production],
  t3.[Task deadline] [Flight Date]
from MSP_EpmTask_UserView t1
left join MSP_EpmTask_UserView t2
  on t1.[Project nr] = t2.[Project nr]
  and t2.[Task Type Production] = 'Leave Production'
left join MSP_EpmTask_UserView  t3
  on t1.[Project nr] = t3.[Project nr]
  and t3.[Task Type Production] = 'Flight Date'
where t1.[Task Type Production] = 'Pack'

请参阅SQL Fiddle with Demo

所有查询的结果是：

| PROJECT NR |       PACK | LEAVE PRODUCTION | FLIGHT DATE |
------------------------------------------------------------
|        123 | 2013-04-01 |       2013-04-03 |  2013-04-09 |

Answer 2

您可以尝试使用传统的相关子查询方法创建交叉表或数据透视表：

select [Project nr]
    , (select [Task deadline] from MSP_EpmTask_UserView where [Project nr] = t.[Project nr] and [Task Type Production] = 'Pack') as Pack
    , (select [Task deadline] from MSP_EpmTask_UserView where [Project nr] = t.[Project nr] and [Task Type Production] = 'Leave Production') as [Leave Production]
    , (select [Task deadline] from MSP_EpmTask_UserView where [Project nr] = t.[Project nr] and [Task Type Production] = 'Flight Date') as [Flight Date]
from MSP_EpmTask_UserView t
group by [Project nr]
order by [Project nr]

/*
Project nr  Pack       Leave Production Flight Date
----------- ---------- ---------------- -----------
123         2013-04-01 2013-04-03       2013-04-09
*/

我在SQL Server 2008中完成了这项工作，它具有漂亮的date数据类型，但你可以用stings或datetime来做到这一点。这也假定特定项目的每个日期只有一个。

另外，如果可能，请尽量不要在数据库对象名称中放置空格或其他特殊字符，这些字符会强制您用括号分隔它们。

使用一个sql语句在数据透视表中创建多个列

2 个答案: