我需要一个 true 迭代器,它的工作原理如下:
var haystackObj = {
'needle': 'abc',
'prop2': {
'prop1': 'def',
'prop2': {
'needle': 'ghi',
},
'needle': 'jkl',
},
};
var needleKey = 'needle';
var iterator = {
next: function () {
/*
* WHAT CODE GOES HERE?
*
* Should return the next property, recursively, with the name
* equal to needleKey, of haystackObj.
*
*/
}
};
var value = iterator.next();
console.log(value); // -> 'abc'
value = iterator.next();
console.log(value); // -> 'ghi'
value = iterator.next();
console.log(value); // -> 'jkl'
我认为这对于for(k in o)和一流的延续来说是微不足道的,但JS并没有那些。
编辑:我只能扫描一次haystackObj。EDIT2:我不正在寻找"一种迭代对象属性的方法。"我正在寻找iterator对象属性。 这是一个巨大的差异。这个问题并不像第一眼看上去那么微不足道。
答案 0 :(得分:7)
JS不保证属性顺序。不同的引擎表现不同。 (某些引擎基于字母顺序,其他基于最后添加的顺序。)
因此无法满足您的要求。
如果您只是想要一个迭代器而不需要了解订单,您可以看一下这个问题/答案:How to simulate JavaScript yield?
这是关于属性顺序的the spec says:
未指定枚举属性的机制和顺序(第一个算法中的步骤6.a,第二个算法中的步骤7.a)。枚举期间可以删除要枚举的对象的属性。如果删除枚举期间尚未访问的属性,则不会访问该属性。如果在枚举期间将新属性添加到要枚举的对象,则无法保证在活动枚举中访问新添加的属性。在任何枚举中不得多次访问属性名称。
但实际上,您可以从大多数浏览器中获得某个订单:Elements order in a "for (… in …)" loop
我看到实现虚假生成器的唯一方法(根据实际上适合您的顺序)将复制您的对象,并在需要时删除副本的扫描属性。这意味着您不会重新扫描两次相同的属性。一些代码示例:
var Iterator = function() {
var copy = $.extend(haystackObj, true);
// ^ using jQuery's extend for a quick function, but use w/e you want.
// Anyway keep it in a closure. This copy will have its properties deleted
// after each iteration.
return {
next: function next() {
var found = false,
needle;
for (var prop in copy) {
if (typeof copy[prop] === 'object') {
// Since next() doesn't take any argument...
// That's a bad solution. You should use an inner function
// to recurse. But I'm going to bed right now!
var copyCopy = $.extend(copy, true);
copy = copy[prop];
found = next();
copy = copyCopy;
}
else {
if (prop === needleKey) {
found = true;
}
}
if (found) {
needle = copy[prop];
}
// Delete the current property to simulate a real generator.
delete copy[prop];
if (found) {
return needle;
}
}
}
};
};
// Usage:
var iterator = Iterator();
iterator.next(); // "abc"
此代码不起作用(请参阅jsfiddle),我将要睡觉了。但你可以看到它的发展方向以及如何制作东西。
答案 1 :(得分:1)
虽然Florian Margaine的回答指出属性的顺序依赖于js引擎,但这个解决方案适用于chrome。我做了一些调整,但这里是http://jsfiddle.net/6zCkJ/3/: 编辑(此解决方案在OP之前完成,表示树只能处理一次)
var needleKey = 'needle';
var currIndex = 0;
var runningIndex = 0;
var getValueByIndex = function (obj) {
var objToSearch = obj || haystackObj;
for (var x in objToSearch) {
if (x == needleKey) {
if (runningIndex == currIndex) {
currIndex += 1;
return objToSearch[x];
}
runningIndex += 1;
} else if (typeof objToSearch[x] == 'object') {
var found = getValueByIndex(objToSearch[x]);
if (found) return found;
}
}
}
var iterator = {
next: function () {
runningIndex = 0;
return getValueByIndex(0);
}
};
另一种仅在一次遍历树的方法如下http://jsfiddle.net/6zCkJ/6/。问题是每当针更新时你必须加载values数组:
var currIndex = 0;
var valuesArray = [];
var loadValues = function (obj) {
var objToSearch = obj || haystackObj;
for (var x in objToSearch) {
if (x == needleKey) {
valuesArray.push(objToSearch[x])
} else if (typeof objToSearch[x] == 'object') {
loadValues(objToSearch[x]);
}
}
}
loadValues();
console.log(valuesArray);
var iterator = {
next: function () {
return valuesArray[currIndex++];
}
};
编辑:到目前为止,此处发布的所有答案都涉及必须至少导航整个树一次或多次,这不是OP正在寻找的内容,包括必须复制对象并在遍历时删除属性。有一个解决方案,其中涉及在元数据遍历时标记对象,允许您在下次遇到对象时跳过对象。使用我的第一种方法,添加这些优化并希望完成OP请求的内容将是相当简单的。
好吧,所以我无法抗拒试图让它发挥作用。我是这样做的http://jsfiddle.net/6zCkJ/12/。您可以看到我将找到的对象存储在foundObjects对象中,其中键由该对象的路径组成,因此您可以快速查找以查看它是否已经被递归。 numFound用于正确递增运行索引。我没有对此进行过大量测试,但这应该是一个好的开始:
var Iterator = function () {
var needleKey = 'needle';
var currIndex = 0;
var runningIndex = 0;
var foundObjects = {};
var getValueByIndex = function (obj,currentPath) {
var objToSearch = obj || haystackObj;
for (var x in objToSearch) {
currentPath += x + '_';
if (x == needleKey) {
if (runningIndex == currIndex) {
currIndex += 1;
if (!foundObjects[currentPath]) {
foundObjects[currentPath] = {
numFound: 0,
finished: false
};
}
foundObjects[currentPath].numFound += 1;
return objToSearch[x];
}
runningIndex += 1;
} else if (typeof objToSearch[x] == 'object') {
if (foundObjects[currentPath] && foundObjects[currentPath].finished) {
runningIndex += foundObjects[currentPath].numFound;
} else {
var found = getValueByIndex(objToSearch[x],currentPath);
if (found) {
return found;
}
}
}
if (!foundObjects[currentPath]) {
foundObjects[currentPath] = {
numFound: 0,
finished: true
};
}
foundObjects[currentPath].finished = true;
}
}
this.next = function () {
runningIndex = 0;
return getValueByIndex(0,'');
}
};
var iterator = new Iterator();
var value = iterator.next();
答案 2 :(得分:1)
假设我理解正确,并牢记这不是“真正的收益”,并将所有代码放在您似乎想要的地方,
var iterator = {
next: function () {
/*
* WHAT CODE GOES HERE?
*
* Should return the next property, recursively, with the name
* equal to needleKey, of haystackObj.
*
*/
var values=[], findneedles;
findneedles = function(o){
var k;
for(k in o){
if(k === needleKey){
values.push(o[k]);
}else if(typeof o[k] === 'object'){
findneedles(o[k]);
}
}
};
findneedles(haystackObj);
this.next = function(){
return values.shift();
};
return values.shift();
}
};
答案 3 :(得分:0)
我将为后人回答这个问题。
在ECMAScript 6中,我们有一个yield语句。但是,让我们说你疯了,你想立刻使用这个功能 。使用traceur-compiler编译为普通的旧JavaScript,我们得到following。
var iterator = function* (object) {
for(var key in object) {
yield key;
for( k of iterator(object[key]) ) {
yield k;
}
}
};
var o = {
a: 10,
b: 11,
c: {
ca: 12,
cb: 13,
},
d: 14,
};
var res = [];
for( key of iterator(o) ) {
res.push(key);
}
res;
var $__generatorWrap = function(generator) {
return $traceurRuntime.addIterator({
next: function(x) {
switch (generator.GState) {
case 1:
throw new Error('"next" on executing generator');
case 3:
throw new Error('"next" on closed generator');
case 0:
if (x !== undefined) {
throw new TypeError('Sent value to newborn generator');
}
case 2:
generator.GState = 1;
if (generator.moveNext(x, 0)) {
generator.GState = 2;
return {
value: generator.current,
done: false
};
}
generator.GState = 3;
return {
value: generator.yieldReturn,
done: true
};
}
},
'throw': function(x) {
switch (generator.GState) {
case 1:
throw new Error('"throw" on executing generator');
case 3:
throw new Error('"throw" on closed generator');
case 0:
generator.GState = 3;
throw x;
case 2:
generator.GState = 1;
if (generator.moveNext(x, 1)) {
generator.GState = 2;
return {
value: generator.current,
done: false
};
}
generator.GState = 3;
return {
value: generator.yieldReturn,
done: true
};
}
}
});
};
var iterator = function(object) {
var $that = this;
var $arguments = arguments;
var $state = 20;
var $storedException;
var $finallyFallThrough;
var $__0;
var $__1;
var $__2;
var $__3;
var $__4;
var $__5;
var key;
var $G = {
GState: 0,
current: undefined,
yieldReturn: undefined,
innerFunction: function($yieldSent, $yieldAction) {
while (true) switch ($state) {
case 20:
$__2 = [];
$state = 21;
break;
case 21:
$__3 = object;
$state = 23;
break;
case 23:
for (var $__4 in $__3) $__2.push($__4);
$state = 25;
break;
case 25:
$__5 = 0;
$state = 17;
break;
case 17:
if ($__5 < $__2.length) {
$state = 12;
break;
} else {
$state = 19;
break;
}
case 11:
$__5++;
$state = 17;
break;
case 12:
key = $__2[$__5];
$state = 13;
break;
case 13:
if (!(key in $__3)) {
$state = 11;
break;
} else {
$state = 15;
break;
}
case 15:
this.current = key;
$state = 1;
return true;
case 1:
if ($yieldAction == 1) {
$yieldAction = 0;
throw $yieldSent;
}
$state = 3;
break;
case 3:
$__0 = $traceurRuntime.getIterator(iterator(object[key]));
$state = 7;
break;
case 7:
if (!($__1 = $__0.next()).done) {
$state = 8;
break;
} else {
$state = 11;
break;
}
case 8:
k = $__1.value;
$state = 9;
break;
case 9:
this.current = k;
$state = 5;
return true;
case 5:
if ($yieldAction == 1) {
$yieldAction = 0;
throw $yieldSent;
}
$state = 7;
break;
case 19:
$state = -2;
case -2:
return false;
case -3:
throw $storedException;
default:
throw "traceur compiler bug: invalid state in state machine: " + $state;
}
},
moveNext: function($yieldSent, $yieldAction) {
while (true) try {
return this.innerFunction($yieldSent, $yieldAction);
} catch ($caughtException) {
$storedException = $caughtException;
switch ($state) {
default:
this.GState = 3;
$state = -2;
throw $storedException;
}
}
}
};
return $__generatorWrap($G);
};
var o = {
a: 10,
b: 11,
c: {
ca: 12,
cb: 13
},
d: 14
};
var res = [];
for (var $__1 = $traceurRuntime.getIterator(iterator(o)), $__0; !($__0 = $__1.next()).done;) {
key = $__0.value;
{
res.push(key);
}
}
res;
JavaScript中的yield
语句可能,但非常不切实际。
var object = {...};
var callback = function (key, value) {
// Do stuff...
return traverse.CONTINUE;
// or return traverse.STOP if you want the iteration to stop
};
traverse(object, callback);
var traverse = (function () {
var _traverse = function (object, callback) {
var key, value, command;
for( key in object ) {
value = object[key];
command = callback(key, value);
if( command === _traverse.STOP ) {
return _traverse.STOP;
}
command = _traverse(value, callback);
if( command === _traverse.STOP ) {
return _traverse.STOP;
}
}
};
_traverse.CONTINUE = 1;
_traverse.STOP = 2;
return _traverse;
})();