Question

以下查询告诉我当天有多少销售。还有多少新用户和学分。

这是我的工作查询（效果很好！）：

SELECT Substring(purchase.`date`,1,10)                       AS `DayDate`, 
                   Sum(Cast(Substring(purchase.`item`, 12) AS UNSIGNED))     AS `Credit`,
                   Count(1)                                                  AS `Sales`,
                   (SELECT Count(*) FROM enswitch_mobile_users WHERE Date(purchase.`date`) = Substring(enswitch_mobile_users.`creation_date`,1,10))  AS `New_users`
                        FROM   (SELECT item, date 
                                    FROM enswitch_new_iphone_purchases WHERE `status`=1
                                    UNION 
                                    SELECT item, date 
                                    FROM enswitch_new_android_purchases WHERE `status`=1) AS `purchase` 
                        WHERE purchase.`date` >= :from_date AND purchase.`date` <= :to_date
                GROUP  BY `DayDate` 
                ORDER  BY `DayDate` DESC

我在这里搜索3个表格。 enswitch_new_android_purchases enswitch_new_iphone_purchase 它们都有item，user_id，status和date列。一个条目的示例：

date：2012-08-01 16:24:30 item：xsalnx.sip.70 user_id：1337 status：1

同时从enswitch_mobile_users（id，creation_date，移动ID，...）中提取mobile_users金额，并将其与特定日期分组。

我想要做的是添加测试，如果购买的用户或新用户是测试人员。如果是这样，我想在我的查询中忽略这些数据。

我将测试人员保存在一张名为： enswitch_testing_devices（id，name，mobile_id）。

我可以使用enswitch_mobile_users（mobile_id列）加入数据。

到目前为止，我试图让它工作但没有运气.. 我该怎么做这个查询？

Answer 1

尝试下面 - 只需在获得用户时添加一个子句 - 获取除测试之外的所有用户。现在，示例数据和结构表将有所帮助。（我想你可以重新编写查询。）

SELECT Substring(purchase.`date`,1,10)                       AS `DayDate`, 
                   Sum(Cast(Substring(purchase.`item`, 12) AS UNSIGNED))     AS `Credit`,
                   Count(1)                                                  AS `Sales`,
                   (
                        SELECT Count(*) 
                        FROM enswitch_mobile_users 
                        WHERE 
                            Date(purchase.`date`) = Substring(enswitch_mobile_users.`creation_date`,1,10) 
                            AND enswitch_mobile_users.mobile_id NOT IN ( select mobile_id from enswitch_testing_devices WHERE 'is tester')
                    )  AS `New_users`
                        FROM   (SELECT item, date 
                                    FROM enswitch_new_iphone_purchases WHERE `status`=1
                                    UNION 
                                    SELECT item, date 
                                    FROM enswitch_new_android_purchases WHERE `status`=1) AS `purchase` 
                        WHERE purchase.`date` >= :from_date AND purchase.`date` <= :to_date
                GROUP  BY `DayDate` 
                ORDER  BY `DayDate` DESC

Answer 2

我设法解决了这个问题。

如果有人想知道的话。

function search_daily_sales($from_date, $to_date ,$show_testers)
{
        // If not showing the testers
    if ($show_testers === false) 
    {
        $sql = "SELECT Substring(purchase.`date`,1,10)                            AS `DayDate`,
                        Sum(CASE WHEN td.mobile_id IS NULL 
                            THEN Cast(Substring(purchase.`item`, 12) AS UNSIGNED) 
                            ELSE '0' END)                                         AS `Credit`,
                        Sum(CASE WHEN td.mobile_id IS NULL THEN '1' ELSE '0' END) AS `Sales`,
                        (SELECT Count(*) FROM enswitch_mobile_users 
                            WHERE 
                                Date(purchase.`date`) = Substring(enswitch_mobile_users.`creation_date`,1,10)
                            AND enswitch_mobile_users.`mobile_id` NOT IN (SELECT mobile_id FROM enswitch_testing_devices))  AS `New_users`,
                    MIN(CASE WHEN td.mobile_id IS NULL THEN '0' ELSE '1' END)    AS `tester`

                    FROM   (SELECT item, date, user_id
                                FROM enswitch_new_iphone_purchases WHERE `status`=1
                                UNION 
                                SELECT item, date, user_id
                                FROM enswitch_new_android_purchases WHERE `status`=1) AS `purchase` 

                    LEFT JOIN enswitch_mobile_users mu ON mu.id = purchase.user_id
                    LEFT JOIN enswitch_testing_devices td ON td.mobile_id = mu.mobile_id

                    WHERE purchase.`date` >= :from_date AND purchase.`date` <= :to_date
            GROUP  BY `DayDate` 
            ORDER  BY `DayDate` DESC";
    }
    else 
    {
        $sql = "SELECT Substring(purchase.`date`,1,10)                       AS `DayDate`, 
               Sum(Cast(Substring(purchase.`item`, 12) AS UNSIGNED))     AS `Credit`,
               Count(1)                                                  AS `Sales`,
               (SELECT Count(*) FROM enswitch_mobile_users WHERE Date(purchase.`date`) = Substring(enswitch_mobile_users.`creation_date`,1,10))  AS `New_users`
                    FROM   (SELECT item, date 
                                FROM enswitch_new_iphone_purchases WHERE `status`=1
                                UNION 
                                SELECT item, date 
                                FROM enswitch_new_android_purchases WHERE `status`=1) AS `purchase` 
                    WHERE purchase.`date` >= :from_date AND purchase.`date` <= :to_date
            GROUP  BY `DayDate` 
            ORDER  BY `DayDate` DESC";
    }

    $result = DB::query(Database::SELECT, $sql)->bind(':from_date', $from_date)->
                                                bind(':to_date', $to_date)->execute();

return $result;
}

SQL连接与其他表并添加案例

2 个答案: