如何返回包含文件夹中所有文件的文件数组以及子文件夹,我的方法只适用于文件夹,而且不包含子文件夹。
public File[] listf(String directoryName) {
// .............list file
File directory = new File(directoryName);
// get all the files from a directory
File[] fList = directory.listFiles();
for (File file : fList) {
if (file.isFile()) {
System.out.println(file.getAbsolutePath());
} else if (file.isDirectory()) {
listf(file.getAbsolutePath());
}
}
System.out.println(fList);
return fList;
}
答案 0 :(得分:77)
使用您当前的代码,进行此调整:
public void listf(String directoryName, List<File> files) {
File directory = new File(directoryName);
// Get all files from a directory.
File[] fList = directory.listFiles();
if(fList != null)
for (File file : fList) {
if (file.isFile()) {
files.add(file);
} else if (file.isDirectory()) {
listf(file.getAbsolutePath(), files);
}
}
}
}
答案 1 :(得分:28)
使用Apache commons的FileUtils。
listFiles
public static Collection<File> listFiles(File directory,
String[] extensions,
boolean recursive)
Finds files within a given directory (and optionally its subdirectories) which match an array of extensions.
Parameters:
directory - the directory to search in
extensions - an array of extensions, ex. {"java","xml"}. If this parameter is null, all files are returned.
recursive - if true all subdirectories are searched as well
Returns:
an collection of java.io.File with the matching files
答案 2 :(得分:18)
您可以返回List
而不是数组,事情变得更简单。
public static List<File> listf(String directoryName) {
File directory = new File(directoryName);
List<File> resultList = new ArrayList<File>();
// get all the files from a directory
File[] fList = directory.listFiles();
resultList.addAll(Arrays.asList(fList));
for (File file : fList) {
if (file.isFile()) {
System.out.println(file.getAbsolutePath());
} else if (file.isDirectory()) {
resultList.addAll(listf(file.getAbsolutePath()));
}
}
//System.out.println(fList);
return resultList;
}