我有一张这样的表:
+----+----------+----------+----------------+----------------------------------+
| id | users_id | files_id | shared_user_id | shared_date |
+----+----------+----------+----------------+----------------------------------+
| 3 | 1 | 1 | 2 | 2013-01-31 14:27:06.523908+00:00 |
| 2 | 1 | 1 | 2 | 2013-01-31 14:25:37.760192+00:00 |
| 4 | 1 | 3 | 2 | 2013-01-31 14:46:01.089560+00:00 |
| 5 | 1 | 1 | 3 | 2013-01-31 14:50:54.917337+00:00 |
现在我想知道共享该文件的每个文件的所有者。对于文件1,users_id为1.我想从默认的Django auth_user表中获取users_id 1的名称。我想获取每个文件的用户名。我怎么能这样做?
#models.py
from django.db import models
from django.contrib.auth.models import User
class File(models.Model):
users = models.ForeignKey(User)
file_name = models.CharField(max_length=100)
type = models.CharField(max_length=10)
source = models.CharField(max_length=100)
start_date = models.TextField()
end_date = models.TextField()
duration = models.TextField()
size_overview = models.IntegerField()
size = models.TextField()
flag = models.TextField()
#delete_date = models.CharField(max_length=100, null=True, blank=True)
class Share(models.Model):
users = models.ForeignKey(User)
files = models.ForeignKey(File)
shared_user_id = models.IntegerField()
shared_date = models.TextField()
class Host(models.Model):
name = models.TextField()
full_path = models.TextField()
答案 0 :(得分:1)
正如我之前所说,你的模型结构有点奇怪 - 特别是Share.shared_user
应该是ForeignKey,而不是IntegerField。在这种情况下,您可以使用users
作为File
表格,User
从Share
到through
,将class File(models.Model):
users = models.ManyToManyField(User, through='Share')
设置为File
来提供帮助:
my_file.users.count()
现在给出一个{{1}}个实例,您可以这样做:
{{1}}