Question

我试图从我选择的节点后的节点获取值。到目前为止，我已经能够将整个节点信息作为var获取，但我仍然坚持如何仅获取该值。

我的xml看起来像是

<COLUMN>
<NAME>Addr1</NAME>
<VALUE>1234 my street</VALUE>
</COLUMN>

我得到这样的节点

var address = (from c in contactInfo.Descendants("NAME")
                                   where c.Value == "Addr1"
                               select c.NextNode).Single();

由于

Answer 1

尝试：

(address as XElement).Value

Answer 2

NextNode返回XNode，而您需要XElement：

var address = (from c in doc.Descendants("NAME")
    where c.Value == "Addr1"
    select c.NextNode).OfType<XElement>().Single().Value;

我宁愿避免将它全部放在一行上并执行以下操作以添加一些额外的检查：

var address = (from c in doc.Descendants("NAME")
                where c.Value == "Addr1"
                select c.NextNode).Single();
var element = address as XElement;
if (element != null) {
    string value = element.Value;
}

Answer 3

var node = contactInfo.Descendants("COLUMN")
                  .SingleOrDefault(c => c.Element("NAME").Value.Equals("Addr1"))

if (node != null)
     var result = node.Element("VALUE").Value;

Answer 4

您应该选择COLUMN元素，而不是搜索NAME元素：

var address = (from c in contactInfo.Descendants("COLUMN")
               where (string)c.Element("NAME") == "Addr1"
               select (string)c.Element("VALUE")).Single();

与方法语法相同：

var address = contactInfo.Descendants("COLUMN")
                         .Where(c => (string)c.Element("NAME") == "Addr1")
                         .Select(c => (string)c.Element("VALUE"))
                         .Single();

此外，您应该完全确定始终只存在一个名为Addr1的列元素。否则Single()将抛出异常。

XML从nextNode获取值

4 个答案: