Question

我正在尝试从json_encode的sql结果创建一个关联数组。

这是我的代码：

$timelineQuery = "SELECT * FROM timeline_table";
$contentQuery = "SELECT * FROM content_table";
$picQuery = "SELECT * FROM pic_table";

$sql = mysql_query($timelineQuery) or die(mysql_error()); 
$sql2 = mysql_query($contentQuery) or die(mysql_error());
$sql3 = mysql_query($picQuery) or die(mysql_error());   

$mainArray = array(
    'timeline' => $timelineArray = array(
        'content' => $contentArray = array(
            'pictures' => $picArray = array(),
        ),
    ),
);

while($row = mysql_fetch_assoc($sql)) { 
    $timelineArray[] = $row;            
}
while($row2 = mysql_fetch_assoc($sql2)) {
    $contentArray[] = $row2;
}
while($row3 = mysql_fetch_assoc($sql3)) {
    $picArray[] = $row3;
}
echo stripslashes(json_encode($mainArray));

如果我按原样json_encode我的$ mainArray，返回的json具有我正在寻找的语法，但是我没有能够填充数组而不将它添加到我的数组末尾。

{"timeline":{"content":{"pictures":[]}}}

Answer 1

第一

while($row = mysql_fetch_assoc($sql)) { 
    $timelineArray[] = $row;            
}
while($row2 = mysql_fetch_assoc($sql2)) {
    $contentArray[] = $row2;
}
while($row3 = mysql_fetch_assoc($sql3)) {
    $picArray[] = $row3;
}

然后：

    $mainArray = array(
        'timeline' => $timelineArray = array(
            'content' => $contentArray = array(
                'pictures' => $picArray = array(),
            ),
        ),
    );
echo stripslashes(json_encode($mainArray));

您使用空数组定义了数组，但未更新状态。

从sql结果为PHP创建一个关联数组，用于json

1 个答案: