Question

我正在尝试为CRUD应用程序添加Apache Tiles.Am得到以下错误

HTTP Status 500 - Could not resolve view with name 'addEmployee' in servlet with name 'HelloHibernate'

输入例外报告

消息无法解析名称为“HelloHibernate”的servlet中名为“addEmployee”的视图

说明服务器遇到内部错误，导致无法完成此请求。

例外

javax.servlet.ServletException: Could not resolve view with name 'addEmployee' in servlet with name 'HelloHibernate'
    org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1042)
    org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:798)
    org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:716)
    org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:647)
    org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:552)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:617)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:717)

的web.xml

 <?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
  <servlet>
    <servlet-name>HelloHibernate</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
      <param-name>contextConfigLocation</param-name>
      <param-value>/WEB-INF/HelloHibernate-servlet.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>HelloHibernate</servlet-name>
    <url-pattern>*.html</url-pattern>
  </servlet-mapping>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
  </welcome-file-list>
</web-app>

tiles.xml

 <?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE tiles-definitions PUBLIC
       "-//Apache Software Foundation//DTD Tiles Configuration 2.0//EN"
       "http://tiles.apache.org/dtds/tiles-config_2_0.dtd">
  <tiles-definitions> 
  <definition name="base.definition" template="/WEB-INF/views/mainTemplate.jsp">
    <put-attribute name="title" value=""></put-attribute>
    <put-attribute name="header" value="/WEB-INF/views/header.jsp"></put-attribute>
    <put-attribute name="body" value=""></put-attribute>
    <put-attribute name="footer" value="/WEB-INF/views/footer.jsp"></put-attribute>
  </definition>

  <definition name="base.definition" template="addEmployee">
  <put-attribute name="title" value="Employee Data Form"></put-attribute>
  <put-attribute name="body" value="/WEB-INF/views/addEmployee.jsp"></put-attribute>
  </definition>

  <definition name="base.definition" template="employeesList">
  <put-attribute name="title" value="/WEB-INF/views/employeesList.jsp"></put-attribute>
  </definition>
  </tiles-definitions>

Answer 1

你的Tiles声明有点混乱。如果我理解你的意图，我会怎么做。

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE tiles-definitions PUBLIC
   "-//Apache Software Foundation//DTD Tiles Configuration 2.0//EN"
   "http://tiles.apache.org/dtds/tiles-config_2_0.dtd">
<tiles-definitions> 
    <definition name="base.definition" template="/WEB-INF/views/mainTemplate.jsp">
        <put-attribute name="title" value=""></put-attribute>
        <put-attribute name="header" value="/WEB-INF/views/header.jsp"></put-attribute>
        <put-attribute name="body" value=""></put-attribute>
        <put-attribute name="footer" value="/WEB-INF/views/footer.jsp"></put-attribute>
    </definition>

    <definition name="addEmployee" extends="base.definition">
        <put-attribute name="title" value="Employee Data Form"></put-attribute>
        <put-attribute name="body" value="/WEB-INF/views/addEmployee.jsp"></put-attribute>
    </definition>

    <definition name="employeesList" extends="base.definition">
        <put-attribute name="title" value="/WEB-INF/views/employeesList.jsp"></put-attribute>
    </definition>
</tiles-definitions>

在最后2个定义中，我将template属性更改为name个属性，并将现有name属性更改为extends属性。

Java，Spring 3.0.Apache Tiles 2.2 .2错误：无法在名为'HelloHibernate'类型的servlet中解析名为'addEmployee'的视图异常报告

1 个答案: