Question

我的联系表格位于：siteurl.com/help/contact 当他们点击发送按钮时，他们会发送到一个页面：siteurl.com/ext/contact/contactpost.php - 这会将表单发送到电子邮件。

但是，在mail（）函数之后，我使用标题直接将它们发送回siteurl.com/help/contact，我希望它显示警报，如果它们来自siteurl.com/ext/contact/contactpost .PHP

我目前有这个（网址会因使用$ _SERVER ['SERVER_NAME']而改变）：

$url = "http://". $_SERVER['SERVER_NAME'] . "/ext/contact/contactpost.php";
if( $_SERVER['HTTP_REFERER'] == $url ){

    // The user was referred by the correct page, so you're good to go
    alert('Thanks, your message was submitted!');

}

回显$ url给了我正确的siteurl.com/ext/contact/contactpost.php但没有提醒！

任何帮助？

Answer 1

警报不是PHP函数，这是一个javascript函数（客户端不是服务器端）！

修复代码：

$url = "http://". $_SERVER['SERVER_NAME'] . "/ext/contact/contactpost.php";
if( $_SERVER['HTTP_REFERER'] == $url ){

    // The user was referred by the correct page, so you're good to go
    echo "<script language='javascript' type='text/javascript'>";
     echo "alert('Thanks, your message was submitted!');";
    echo "</script>";


}

如果来自网址，则显示警报

1 个答案: