Question

章节表

CHID | Name | Active | Order
 1     Ch2      Y        2
 2     Ch5      N        10
 3     Ch1      Y        1

页面表

PID | Name  | Active | CHID | Order
 1    Ch1P1     Y       1       1
 2    Ch1P2     Y       1       2
 3    Ch2P2     Y       3       2
 4    Ch2P1     Y       3       1
 5    Ch5P1     N       2       1

当前结果列出了每一章，但也列出了每章下的每一页。我使用当前脚本的'foreach'部分并将其与一些Dreamweaver构建的PHP合并。

我正在寻找：

Ch1
    Ch1P1
    Ch1P2
Ch2
    Ch2P1
    Ch2P2

我目前的php / mysql脚本。

    $myarray = array();
    mysql_select_db($database, $connection);
    $query_GetModuleChaptersPages = sprintf("SELECT chapters.CHID, chapters.Chapter_Name AS ChapterName, chapters.MID, chapters.`Order` AS ChapterOrder, pages.PID, pages.Page_Name AS PageName, pages.CHID, pages.Is_Active, pages.`Order` AS PageOrder FROM chapters, pages WHERE chapters.MID = 1"));
    $GetModuleChaptersPages = mysql_query($query_GetModuleChaptersPages, $connection) or die(mysql_error());
    $row_GetModuleChaptersPages = mysql_fetch_assoc($GetModuleChaptersPages);
    $totalRows_GetModuleChaptersPages = mysql_num_rows($GetModuleChaptersPages);

    while ($row = mysql_fetch_array($GetModuleChaptersPages, MYSQL_ASSOC)) { $myarray[$row['ChapterName'] ][]  = $row['PageName']; }

    print "<ul>";
    foreach ($myarray as $key => $val) {
        print "<li><h5>";
        print $key;
        print "</h5><ul>";
        for($i=0;$i<count($val);$i++){
            print "<li>";
            print $val[$i];
            print "</li>";
        }
        print "</ul></li>";
    }
    print "</ul>";

Answer 1

蛮力的方式。

//get all the chapters we want, add criteria as needed
$chapterQuery = "SELECT * FROM `chapters` ORDER BY `order`";
$chapterResult = mysql_query($chapterQuery);
while ($row = mysql_fetch_assoc($chapterResult)) {
    $chapters[] = $row;
}

//get all the pages we want, add criteria as needed
$pagesQuery = "SELECT * FROM `pages` ORDER BY `order`";
$pagesResult = mysql_query($pagesQuery);
while ($row = mysql_fetch_assoc($pagesResult)) {
    $pages[$row['CHID']][$row['order']] = $row;
}

echo "<ul>";
foreach ($chapters as $chapter) {
    echo "<li><h5>" . $chapter['Name'] . "</h5><ul>";
    foreach ($pages[$chapter['CHID']] as $page) {
        echo "<li>".$page['Name']."</li>";
    }
    echo "</ul></li>";
}
echo "</ul>";

这里的关键是使用章节id作为第一个键将页面添加到pages数组中，将第二个键添加到我按顺序排列的页面中，但你可以使用[]代替[$ row ['order']]

Answer 2

如果您不想在输出之前将它们存储（缓存）在数组中：

$data=array();
$result=$mysqli->query("SELECT chapters.chid,chapters.name as cname,pages.pid,pages.name as pname FROM chapters LEFT JOIN pages ON (chapters.chid=pages.chid) WHERE chapters.active='Y' and pages.active='Y' ORDER BY chapters.order ASC,pages.order ASC");
while($row=$result->fetch_assoc())
{
    if(empty($data[$row["chid"]))
        $data[$row["chid"]]=array("name"=>$row["cname"],"pages"=>array());
    $data[$row["chid"]]["pages"][$row["pid"]=$row["pname"];
}
echo "<ul>";
foreach($data as $chid=>$chapter)
{
    echo "<li><h5>".htmlentities($chapter["name"],ENT_COMPAT,"UTF-8")."</h5><ul>";
    foreach($chapter["pages"] as $page)
    {
        echo "<li>".htmlentities($page,ENT_COMPAT,"UTF-8")."</li>";
    }
    echo "</ul></li>";
}
echo "</ul>";

如果要在提取时输出：

$ch=$mysqli->query("SELECT chid,name FROM chapters WHERE active='Y' ORDER BY `order` ASC"); $pg=$mysqli->prepare("SELECT pid,name FROM pages WHERE active='Y' AND chid=? ORDER BY `order` ASC"); $pg->bind_param("i",$chid); echo "<ul>"; while($row=$ch->fetch_assoc()) { echo "<li><h5>".htmlentities($row["name"],ENT_COMPAT,"UTF-8")."</h5><ul>"; $chid=intval($row["chid"]); $pg->execute(); $pgrst=$pg->get_result(); while($pages=$pgrst->fetch_assoc()) { echo "<li>".htmlentites($pages["name"],ENT_COMPAT,"UTF-8")."</li>"; } echo "</ul></li>"; } echo "</ul>";

请注意，这是未经过测试的，所以不要指望它可以正常使用＆＃34;开箱即用＆＃34 ;;但它应该指向你的工作轨道。

试着排序＆＃39;章节＆＃39;和＆＃39;页面＆＃39;在PHP中基于＆＃39; chapter.Order＆＃39;和＆＃39; page.Order＆＃39;

2 个答案: