Question

我有一个看起来像这样的表格：

class AddressSearchForm(forms.Form):
    """
        A form that allows a user to enter an address to be geocoded
    """
    address = forms.CharField()

我没有存储此值，但是，我正在对地址进行地理编码并检查以确保其有效：

def clean_address(self):
    address = self.cleaned_data["address"]
    return geocode_address(address, True)

地理编码功能如下所示：

def geocode_address(address, return_text = False):
    """ returns GeoDjango Point object for given address
        if return_text is true, it'll return a dictionary: {text, coord}
        otherwise it returns {coord}
    """ 
    g = geocoders.Google()
    try:
        #TODO: not really replace, geocode should use unicode strings
        address = address.encode('ascii', 'replace')            
        text, (lat,lon) = g.geocode(address)
        point = Point(lon,lat)
   except (GQueryError):
       raise forms.ValidationError('Please enter a valid address')
    except (GeocoderResultError, GBadKeyError, GTooManyQueriesError):
    raise forms.ValidationError('There was an error geocoding your address. Please try again')
    except:
        raise forms.ValidationError('An unknown error occured. Please try again')

    if return_text:
         address = {'text':text, 'coord':point}
    else:
        address = {'coord':point}

    return address

我现在需要做的是创建一个视图，使用地址数据查询模型以过滤结果。我无法弄清楚如何做到这一点。如果可能的话，我想使用CBV。我可以使用FormView来显示表单，并使用ListView来显示查询结果，但是如何在两者之间传递表单数据？

提前致谢。

更新：我知道如何查询我的模型来过滤结果。我只是不知道如何使用表单和基于类的视图正确组合，以便我可以访问我的过滤器的cleaning_data。 e.g：

流程应该是：

1）在get上显示表单 2）在帖子上提交表格并验证（地理编码地址） 3）运行查询并显示结果

address = form.cleaned_data['address']
point = address['coord']
qs = model.objects.filter(point__distance_lte=(point, distance)

Answer 1

这类似于这里提出的问题，或者我会说两个问题的组合。

Django: Search form in Class Based ListView
Search multiple fields of django model without 3rd party app
django simple approach to multi-field search（如果您的模型类似于此问题中提到的模型）

请查看以上问题及其答案，如果您还有任何疑问，请回复此答案。

更新1

from django.views.generic.base import TemplateResponseMixin, View
from django.views.generic.edit import FormMixin
from django.views.generic.list import MultipleObjectMixin

class SearchView(FormMixin, MultipleObjectMixin, TemplateResponseMixin, View):
    model = SomeModel
    form_class = AddressSearchForm
    template = "search.html"

    def get_queryset():
        ## Override it here
        pass

    def post():
        ## If your form is invalid then request won't reach here
        ## because FormMixin is in left most position
        ## do something
        ## call self.render_to_response()

    def form_valid():
        ## Your form is valid do something
        ## if form is invalid then next method will be called
        pass

    def form_invalid(self):
        ## form is not valid
        ## render to some template

有用的链接：

相关问题：

Django - Mixing ListView and CreateView

Answer 2

好的，这是基于psjinx方向的最终工作的通用版本：

from django.views.generic.base import TemplateResponseMixin, View
from django.views.generic.edit import FormMixin
from django.views.generic.list import MultipleObjectMixin

class SearchView(FormMixin, MultipleObjectMixin, TemplateResponseMixin, View):
    """
     A View which takes a queryset and filters it via a validated form submission
    """
    queryset = {{ initial queryset }} # you can use a model here too eg model=foo
    form_class = {{ form }}

    def get(self, request, *args, **kwargs):
        form_class = self.get_form_class()
        form = self.get_form(form_class)
        return self.render_to_response(self.get_context_data(form=form))

    def post(self, request, *args, **kwargs):
        form_class = self.get_form_class()
        form = self.get_form(form_class)
        if form.is_valid():
            return self.form_valid(form)
        else:
            return self.form_invalid(form)    

    def form_valid(self, form):
        queryset = self.get_queryset()
        search_param = form.cleaned_data['{{ form field }}']
        object_list = queryset.filter({{ filter operation }}=search_param)
        context = self.get_context_data(object_list=object_list, form=form, search_param=search_param)
        return self.render_to_response(context)

Django使用表单输入来查询数据 - 应该很简单，不是（对我来说）

2 个答案:

更新1

有用的链接：

相关问题：