Question

在这种情况下哪种模式会更快？
显然，带帮手的Pattern1看起来更复杂，看起来很干净但是每次调用user_link方法时它都会发送SQL 在这里，它在一页加载时调用最多100次。

哪种方式对基准性能更好？

型式1。有助手

application_helper

def user_link(username)
    link_to User.find_by_username(username).user_profile.nickname, show_user_path(username)
end

视图

<% @topics.order("updated_at DESC").limit(100).each do |topic| %>
    <%= user_link(topic.comment_threads.order("id").last.user.username) if topic.comment_threads.present? %>
<% end %>

PATTERN2。没有帮手。只是查看

<% @topics.order("updated_at DESC").limit(100).each do |topic| %>
    <%= link_to(topic.comment_threads.order("id").last.user.nickname, show_user_path(topic.comment_threads.order("id").last.user.username) ) if topic.comment_threads.present? %>
<% end %>

Answer 1

试

# Topics model
#via scope
scope :get_topic_list, lambda do
  order("updated_at DESC").joins(:comment_threads => :user).limit(100)
end

#via method
def self.get_topic_list
  Topic.order("updated_at DESC").joins(:comment_threads => :user).limit(100)
end

# in your controller or move to model itself (recommened)
@topics = Topic.get_topic_list

# in you view
<% @topics.each do |topic| %>
    <%= link_to(topic.comment_threads.order("id").last.user.nickname, show_user_path(topic.comment_threads.order("id").last.user.username) ) if topic.comment_threads.present? %>
<% end %>

我应该帮帮忙吗？或者这会变慢吗？

1 个答案: