Question

我正在尝试序列化我的代码。

当我使用XmlElement ASP.Net设置类成员的Order属性时，我在这一行上得到了例外;

XmlSerializer serializer = new XmlSerializer(typeof(HotelListResponse));

例外是;

不一致的排序：如果在类的一个成员上使用，所有类似粒子的成员都需要'Order'属性，请在类成员'_hotelId'上使用XmlElement，XmlAnyElement或XmlArray自定义属性显式设置'Order'。

代码是：

 using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())
             {

                 StreamReader responsereader = new  StreamReader(response.GetResponseStream());

                  var responsedata = responsereader.ReadToEnd();
                  xmldoc = (XmlDocument)JsonConvert.DeserializeXmlNode(responsedata);
                  xmldoc.Save(@"C:\New folder\myfile.xml");

                 DataTable dt = new DataTable();
                 DataRow dr;
                 dt.Columns.Add("hotelId");
                 dt.Columns.Add("name");
                 dt.Columns.Add("address1");
                 dt.Columns.Add("address2");
                 dt.Columns.Add("city");
                 dt.Columns.Add("postalCode");
                 dt.Columns.Add("countryCode");
                 dr = dt.NewRow();

                  XmlSerializer serializer = new XmlSerializer(typeof(HotelListResponse));

                 Stream reader = new FileStream(@"C:\New folder\myfile.xml", FileMode.Open);

                 HotelListResponse htype = (HotelListResponse)serializer.Deserialize(reader);
                 dt.ReadXml(@"C:\New folder\myfile.xml");
                 foreach(hoteltype ht in htype.hotel){
                      GridView1.DataSource = dt;
                      GridView1.DataBind();
                  }

                 //responsereader.Close();
                  //request.GetResponse().Close();

             }
         }
         catch (WebException ex)
         { 
             if (ex.Response == null)
                 throw new NullReferenceException("WebException response");
             throw ex;
         }

 }
    [System.SerializableAttribute()] 
    [System.Xml.Serialization.XmlRoot("HotelListResponse")]
     public class HotelListResponse
     {

         [System.Xml.Serialization.XmlElementAttribute("hotel")]
         public hoteltype[] hotel;
         [System.Xml.Serialization.XmlElement(Order = 0)] 
         public hoteltype[] Items {

             get {
                 return this.hotel;
             }
             set {
                 this.hotel = value;
             }
         } 
     }

    [Serializable]    
    [XmlType("hoteltype")]
    public class hoteltype
    {
        hoteltype(){}     

        public int _hotelId;  
        public string _name;   
        public string _address1;     
        public string _address2;    
        public string _city;
        public int _postalCode;  
        public string _countryCode;

        [XmlElement]
        public hoteltype[] htype;

        [System.Xml.Serialization.XmlElement(Order=1)]

        public int hotelId
        { 
            get {
                return _hotelId;
            } 
          set{
              _hotelId = value;
         }
      }
       [System.Xml.Serialization.XmlElement(Order=2)]

      public string name
    {
        get
        {
            return _name;
        }
        set
        {
            _name = value;
        }
    }
    [System.Xml.Serialization.XmlElement(Order=3)]

    public string address1
    {
        get
        {
            return _address1;
        }
        set
        {
            _address1 = value;
        }
    }
    [System.Xml.Serialization.XmlElement(Order=4)]

    public string address2
    {
        get
        {
            return _address2;
        }
        set
        {
            _address2 = value;
        }
    }
    [System.Xml.Serialization.XmlElement(Order=5)]

    public string city
    {
        get
        {
            return _city;
        }
        set
        {
            _city = value;
        }
    }
    [System.Xml.Serialization.XmlElement(Order=6)]

    public int postalCode
    {
        get
        {
            return _postalCode;
        }
        set
        {
            _postalCode = value;
        }
    }
    [System.Xml.Serialization.XmlElement(Order=7)]
    public string countryCode
    {
        get
        {
            return _countryCode;
        }
        set
        {
            _countryCode = value;
        }
    }

}

Answer 1

如异常中所述，只要使用Order=xx，就必须对类中的所有可序列化属性和字段进行排序。但是，_hotelId似乎可能是一个私人支持领域。由于XmlSerializer也会序列化公共字段，因此这可能是无意的。如果_hotelId确实必须公开，但您不希望序列化，那么您可以使用XmlIgnore。

我猜你的课可能看起来像：

[System.SerializableAttribute()] 
public partial class HotelListResponse 
{ 
    [System.Xml.Serialization.XmlElement(Order = 0)] 
    public string SomeOrderedField 
    { 
        get;
        set;
    } 

    // ** Problem may be here
    // Because the field is public, XmlSerializer will try to serialize this
    public int _hotelId; 

    [System.Xml.Serialization.XmlElement(Order = 1)] 
    public int HotelId
    { 
        get
        {
            return _hotelId;
        }
        set
        {
            _hotelId = value;
        }
    }

修改是的，这正是问题

将您的支持字段设为私有 - 这就是您拥有公共属性访问者的原因。

    public int _hotelId;  => private int _hotelId;
    public string _name;  => private string _name;

等

修改

[XmlElement(Order=0)] public hoteltype[] htype;

我也会同时将其更改为某个属性。如果您使用的是.NET 3.5或更高版本，请使用自动支持字段。

[XmlElement(Order=0)] public hoteltype[] htype { get; set; }

修改

如果您系统地应用了上述内容，那么您的可序列化类应如下所示：

[System.SerializableAttribute()] [System.Xml.Serialization.XmlRoot("HotelListResponse")] public class HotelListResponse { // This is bad practice - never make a backing field public //[System.Xml.Serialization.XmlElementAttribute("hotel")] //public hoteltype[] hotel; // Use the >= .Net 3.5 automatic properties - this way you don't need // the backing field at all, which will prevent confusion over // 'what gets serialized' [System.Xml.Serialization.XmlElement(Order = 0)] public hoteltype[] Items { get; set; } } [Serializable] [XmlType("hoteltype")] public class hoteltype { public hoteltype() { } [System.Xml.Serialization.XmlElement(Order = 0)] public hoteltype[] htype { get; set; } [System.Xml.Serialization.XmlElement(Order = 1)] public int hotelId { get; set; } [System.Xml.Serialization.XmlElement(Order = 2)] public string name { get; set; } [System.Xml.Serialization.XmlElement(Order = 3)] public string address1 { get; set; } [System.Xml.Serialization.XmlElement(Order = 4)] public string address2 { get; set; } [System.Xml.Serialization.XmlElement(Order = 5)] public string city { get; set; } [System.Xml.Serialization.XmlElement(Order = 6)] public int postalCode { get; set; } [System.Xml.Serialization.XmlElement(Order = 7)] public string countryCode { get; set; } }

通过序列化/反序列化循环测试上述内容，如下所示：

XmlSerializer serializer = new XmlSerializer(typeof(HotelListResponse)); HotelListResponse X = new HotelListResponse(); X.Items = new hoteltype[2]; X.Items[0] = new hoteltype(); X.Items[0].address1 = "address1"; X.Items[1] = new hoteltype(); X.Items[1].address1 = "address2"; using (Stream writer = new FileStream(@"C:\temp\myfile.xml", FileMode.Create)) { serializer.Serialize(writer, X); writer.Flush(); } Stream reader = new FileStream(@"C:\temp\myfile.xml", FileMode.Open); HotelListResponse htype = (HotelListResponse)serializer.Deserialize(reader);

以下文件反序列化：

<?xml version="1.0"?> <HotelListResponse xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Items> <hotelId>0</hotelId> <address1>address1</address1> <postalCode>0</postalCode> </Items> <Items> <hotelId>0</hotelId> <address1>address2</address1> <postalCode>0</postalCode> </Items> </HotelListResponse>

如何使用XmlElement asp.net显式设置类成员的Order属性

1 个答案: