如何在linux内核中定义和触发我自己的新softirq?

时间:2013-01-13 06:49:05

标签: android c linux-kernel arm softirq

我想在linux内核中创建自己的softirq。这是否是正确的方法:

在模块的init中,我想触发softirq,我将添加一个电话:

394 void open_softirq(int nr, void (*action)(struct softirq_action *))
395 {
396         softirq_vec[nr].action = action;
397 }

在我想要提升softirq的片段中,我将添加对raise_softirq函数的调用:

379 void raise_softirq(unsigned int nr)
380 {
381         unsigned long flags;
382 
383         local_irq_save(flags);
384         raise_softirq_irqoff(nr);
385         local_irq_restore(flags);
386 }

将我的新softirq添加到:

411 /* PLEASE, avoid to allocate new softirqs, if you need not _really_ high
412    frequency threaded job scheduling. For almost all the purposes
413    tasklets are more than enough. F.e. all serial device BHs et
414    al. should be converted to tasklets, not to softirqs.
415  */
416 
417 enum
418 {
419         HI_SOFTIRQ=0,
420         TIMER_SOFTIRQ,
421         NET_TX_SOFTIRQ,
422         NET_RX_SOFTIRQ,
423         BLOCK_SOFTIRQ,
424         BLOCK_IOPOLL_SOFTIRQ,
425         TASKLET_SOFTIRQ,
426         SCHED_SOFTIRQ,
427         HRTIMER_SOFTIRQ,
428         RCU_SOFTIRQ,    /* Preferable RCU should always be the last softirq */
429         MY_NEW_SOFTIRQ
430         NR_SOFTIRQS
431 };

在这里:

 60 char *softirq_to_name[NR_SOFTIRQS] = {
 61         "HI", "TIMER", "NET_TX", "NET_RX", "BLOCK", "BLOCK_IOPOLL",
 62         "TASKLET", "SCHED", "HRTIMER", "RCU", "MY_NEW_SOFTIRQ"
 63 };

问题:

  • 我是对的还是我错过了什么?
  • 这是正确的方法吗?还有其他选择吗?

2 个答案:

答案 0 :(得分:1)

如果你想修补内核并重新编译它,你可能做得对(除非你应该在RCU_SOFTIRQ之前移动它)。

否则,如果您想在内核模块中执行此操作,则必须使用基于SoftIRQ的tasklet在SoftIRQ上下文中执行某些操作:

tasklet_init()用于初始化你。

tasklet_schedule()安排您注册的tasklet。

答案 1 :(得分:0)

静态声明Softirq

通过将您的softirq MY_NEW_SOFTIRQ添加到enum静态声明 char *softirq_to_name[NR_SOFTIRQS]。重新编译内核。

即时注册Softirq

一旦静态声明,我们自己的softirq应该在运行时使用open_softirq()在内核模块中注册。通过raise_softirq()在中断处理程序的退出路径中提升它。