QComboBox不显示其项目列表

时间:2013-01-09 23:00:48

标签: c++ qt qtablewidget qgraphicsscene qcombobox

我的QComboBox问题是QTableWidget的项目删除编辑器。 QTableWidget使用SqlTypeDelegate作为项委托。

当我在QGraphicsScene中绘制QTableWidget(通过QGraphicsProxyWidget)时,未显示QComboBox弹出的可用项列表。 但如果我使用QTableWidget作为普通小部件(不是通过QGraphicsScene \ View绘制),那么QComboBox行为是正常的 - 它显示了项目列表。

如何强制QComboBox显示其项目列表?

以下示例代码:

main.cpp中:

#include <QtGui/QApplication>
#include <QGraphicsScene>
#include <QGraphicsView>
#include <QTableWidget>
#include "sqltypedelegate.h"

int main(int argc, char *argv[])
{
    QApplication app(argc, argv);
    QGraphicsScene scene;
    QTableWidget *table = new QTableWidget(4,2);
    table->setItemDelegate(new SqlTypeDelegate(table));
    QGraphicsProxyWidget *proxy = scene.addWidget(table);
    QGraphicsView view(&scene);
    view.show();
    return app.exec();
}

sqltypedelegate.h:

#include <QItemDelegate>
#include <QStyledItemDelegate>
#include <QModelIndex>
#include <QObject>
#include <QSize>
#include <QComboBox>

class SqlTypeDelegate : public QItemDelegate
{
    Q_OBJECT
public:
    SqlTypeDelegate(QObject *parent = 0);
    QWidget *createEditor(QWidget *parent, const QStyleOptionViewItem &option,
                          const QModelIndex &index) const;
    void setEditorData(QWidget *editor, const QModelIndex &index) const;
    void setModelData(QWidget *editor, QAbstractItemModel *model,
                      const QModelIndex &index) const;
    void updateEditorGeometry(QWidget *editor,
        const QStyleOptionViewItem &option, const QModelIndex &index) const;
};

sqltypedelegate.cpp:

#include <QtGui>
#include "sqltypedelegate.h"

SqlTypeDelegate::SqlTypeDelegate(QObject *parent)
    : QItemDelegate(parent)
{}

QWidget *SqlTypeDelegate::createEditor(QWidget *parent,
    const QStyleOptionViewItem &/* option */,
    const QModelIndex &/* index */) const
{
    QComboBox *editor = new QComboBox(parent);
    editor->addItem(QString("decimal(50)"));
    editor->addItem(QString("integer"));
    editor->addItem(QString("varchar(50)"));
    editor->addItem(QString("char"));

    editor->setEditable(true);
    return editor;
}

void SqlTypeDelegate::setEditorData(QWidget *editor,
                                    const QModelIndex &index) const
{
    QString value = index.model()->data(index, Qt::EditRole).toString();
    QComboBox *comboBox = static_cast<QComboBox*>(editor);
    comboBox->setEditText(value);
}

void SqlTypeDelegate::setModelData(QWidget *editor, QAbstractItemModel *model,
                                   const QModelIndex &index) const
{
    QComboBox *comboBox = static_cast<QComboBox*>(editor);
    model->setData(index, comboBox->currentText(), Qt::EditRole);
}

void SqlTypeDelegate::updateEditorGeometry(QWidget *editor,
    const QStyleOptionViewItem &option, const QModelIndex &/* index */) const
{
    QComboBox *comboBox = static_cast<QComboBox*>(editor);
    comboBox->setGeometry(option.rect);
}

2 个答案:

答案 0 :(得分:2)

最终我找到了解决方案:事件过滤器! 只是潜伏在QEvent :: MouseButtonRelease中,然后调用showPopup。

bool SqlTypeDelegate::eventFilter(QObject *object, QEvent *event)
{
    QComboBox * comboBox = dynamic_cast<QComboBox*>(object);
    if (comboBox)
    {
        if (event->type() == QEvent::MouseButtonRelease)
        {
            comboBox->showPopup();
            return true;
        }
    }
    else
    {
        return QItemDelegate::eventFilter( object, event );
    }
    return false;
}

答案 1 :(得分:1)

我遇到了同样的问题,我的解决方法是在createEditor(...)中添加两行代码。

editor->move(option.rect.x(),option.rect.y());
editor->showPopup();

然后当双击表项时,QComboBox将显示由第二个鼠标按钮触发的弹出项目,并隐藏由第二个鼠标按钮释放触发的弹出项目。这适用于Qt 4.8。

我也尝试了Qt5.0,应用程序在有或没有此解决方法时崩溃了。 我已将此问题报告为错误。