Django - 如何以相同的形式使用多个ModelForm?

时间:2013-01-04 10:16:48

标签: python django modelform django-forms

我需要一次存储数据的4个模型。为此,我正在考虑使用ModelForms。

我已经同时使用2个ModelForm进行了测试,但它无法正常工作。这是代码。

型号:

class Main(models.Model):
    section             = models.ForeignKey(Section)
    user                = models.ForeignKey(User)
    title               = models.CharField(max_length=250)
    date_inserted       = models.DateTimeField(auto_now_add=True)
    date_last_update    = models.DateTimeField(auto_now=True)

    def __unicode__(self):
    return self.title

    # To order in the admin by name of the section
    class Meta:
    ordering = ['date_inserted']


class BicycleAd(models.Model):
    main                = models.ForeignKey(Main)
    bicycleadtype       = models.ForeignKey(BicycleAdType)
    bicycleaditemkind   = models.ForeignKey(BicycleAdItemKind) # MPTT Model
    bicycleadcondition  = models.ForeignKey(BicycleAdCondition)
    country             = models.ForeignKey(GeonamesCountry)       
    city                = models.ForeignKey(GeonamesLocal) 
    date_inserted       = models.DateTimeField(auto_now_add=True)
    date_last_update    = models.DateTimeField(auto_now=True)

    # To order in the admin by name of the section
    class Meta:
    ordering = ['date_inserted']   

形式:

class MainForm(forms.ModelForm):
    class Meta:
    model = Main
    exclude = ('user', 'section')

class BicycleAdForm(forms.ModelForm):
    class Meta:
    model = BicycleAd
    exclude = ('main', 'bicycleadtype', 'bicycleaditemkind', 'bicycleadcondition', 'city')

查看:

def submit_data_entry_view(request):
    form_main      = MainForm(request.POST)
    form_bicyclead = BicycleAdForm(request.POST)

    return render_to_response('app/submit_data_entry.html', {'form_main': form_main, 'form_bicyclead': form_bicyclead}, context_instance=RequestContext(request))

模板:

<form method="post" action="">
    {{form_main}}
    {{form_bicyclead}}
</form>

最后我只在浏览器中输出“form_bicyclead”?我如何一次获得这两个表格?

最诚挚的问候,

1 个答案:

答案 0 :(得分:3)

您是否也使用submit_data_entry_view呈现表单?不应该像 -

def submit_data_entry_view(request):

    if request.method == 'POST': #form submit
        form_main      = MainForm(request.POST)
        form_bicyclead = BicycleAdForm(request.POST)

        #now process and save the form

        return <whatever_you_want>
    elif request.method == 'GET': #first time rendering the form
        form_main      = MainForm()
        form_bicyclead = BicycleAdForm()

        return render_to_response('app/submit_data_entry.html', {'form_main': form_main, 'form_bicyclead': form_bicyclead}, context_instance=RequestContext(request))