Question

任何人都知道如何使用T-SQL查询构建一周的临时表？

我听说有很多类型的计算，Gregorian等等......我的需求是ISO Week No并且绑定到temp表取决于周数。

临时表有两列：ISOWeekNo和WeekName

ISOWeekNo   WeekName
1           01 Jan 2013 To 07 Jan 2013
2           08 Jan 2013 To 14 Jan 2013

如何基于ISO Week No？

在T-SQL查询中以编程方式构建

更新：我想仅传递参数年份。例如：2013

Answer 1

编辑：添加WHERE子句以终止所寻找的年份。

这似乎符合维基百科的描述，我相信还有优化空间。 Mikael，我复制了友好专栏的格式代码，谢谢。由于使用了ISOWEEK datepart。

，此代码将在SQL Server 2008之后使用

use tempdb
go

DECLARE  @Year          SMALLINT = 2013
        ,@FirstISOWKDay DATETIME

;WITH FindISOWEEKFirstDay AS
(
    SELECT DT   = DATEADD(DAY, -7, DATEFROMPARTS(@Year, 1, 1))
    UNION ALL
    SELECT DATEADD(DAY, 1, DT)
    FROM FindISOWEEKFirstDay
    WHERE DATEADD(DAY, 1, DT) < DATEADD(DAY, 14, DATEFROMPARTS(@Year, 1, 1))
)
SELECT TOP 1 @FirstISOWKDay = DT
FROM FindISOWEEKFirstDay
WHERE DATEPART(ISO_WEEK, DT) = 1
ORDER BY DT ASC -- Eliminate probability of arb sorting (Thanks Mikael)
;WITH Base10 (n) AS
(
    SELECT 1    UNION ALL   SELECT 1    UNION ALL   SELECT 1    UNION ALL
    SELECT 1    UNION ALL   SELECT 1    UNION ALL   SELECT 1    UNION ALL
    SELECT 1    UNION ALL   SELECT 1    UNION ALL   SELECT 1    UNION ALL
    SELECT 1    
)
,Base1000 (n) AS
(
    SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL))-1
    FROM Base10 T1, Base10 T2, Base10 T3
)
SELECT   Start      = DATEADD(DAY, n*7, @FirstISOWKDay)
        ,[End]      = DATEADD(DAY, n*7 + 6, @FirstISOWKDay)
        ,Friendly   = CONVERT(VARCHAR(101), DATEADD(DAY, n*7, @FirstISOWKDay), 106)+' To '+CONVERT(VARCHAR(101), DATEADD(DAY, n*7 + 6, @FirstISOWKDay), 106)
        ,ISOWEEK    = DATEPART(ISO_WEEK, DATEADD(DAY, n*7, @FirstISOWKDay))
FROM Base1000
-- Filter to terminate, resulting only in sought year's calendar
WHERE DATEPART(YEAR, DATEADD(DAY, n*7 + 6, @FirstISOWKDay)) = @Year

Answer 2

declare @Year int;
set @Year = 2016;

with C as
(
  select datefromparts(@Year, 1, 1) as D
  union all
  select dateadd(day, 1, C.D)
  from C
  where C.D < datefromparts(@Year, 12, 31)
)
select datepart(iso_week, C.D) as ISOWeekNo,
       convert(varchar(101), min(C.D), 106)+' To '+convert(varchar(101), max(C.D), 106) as WeekName
from C
group by datepart(iso_week, C.D),
         case when datepart(month, C.D) = 12 and
                   datepart(iso_week, C.D) > 50
           then 1
           else 0 
         end
order by min(C.D)
option (maxrecursion 0);

结果：

ISOWeekNo   WeekName
----------- --------------------------
53          01 Jan 2016 To 03 Jan 2016
1           04 Jan 2016 To 10 Jan 2016
2           11 Jan 2016 To 17 Jan 2016
3           18 Jan 2016 To 24 Jan 2016
4           25 Jan 2016 To 31 Jan 2016
5           01 Feb 2016 To 07 Feb 2016
6           08 Feb 2016 To 14 Feb 2016
7           15 Feb 2016 To 21 Feb 2016
.
.
.
47          21 Nov 2016 To 27 Nov 2016
48          28 Nov 2016 To 04 Dec 2016
49          05 Dec 2016 To 11 Dec 2016
50          12 Dec 2016 To 18 Dec 2016
51          19 Dec 2016 To 25 Dec 2016
52          26 Dec 2016 To 31 Dec 2016

如何在T-SQL查询中以编程方式构建ISO周数表？

2 个答案: