如何在data-win-bind中设置ID?

时间:2012-12-27 19:45:00

标签: javascript css windows html5 winjs

我在使用W8的模板时遇到了大麻烦:

    <div class="itemtemplate" data-win-control="WinJS.Binding.Template">
    <div class="item">
        <img class="item-image" src="#" data-win-bind="src: backgroundImage; alt: title" />
        <div class="item-overlay">
            <h4 class="item-title" data-win-bind="textContent: title" style="margin-left: 0px; margin-right: 291.08px;"></h4>
            <h6 class="item-subtitle win-type-ellipsis" data-win-bind="textContent: subtitle"></h6>
        </div>
    </div>
</div>

但是我需要的一些项目有不同的外观我需要添加一个ID,例如这个代码在data.js中:

        var sampleItems = [
        { group: sampleGroups[0], importancia: "top", title: "Item Title: 1", subtitle: "Item Subtitle: 1", description: itemDescription, content: itemContent, backgroundImage: lightGray },
        { group: sampleGroups[0], title: "Item Title: 2", subtitle: "Item Subtitle: 2", description: itemDescription, content: itemContent, backgroundImage: darkGray },
        { group: sampleGroups[0], title: "Item Title: 3", subtitle: "Item Subtitle: 3", description: itemDescription, content: itemContent, backgroundImage: mediumGray },
        { group: sampleGroups[0], title: "Item Title: 4", subtitle: "Item Subtitle: 4", description: itemDescription, content: itemContent, backgroundImage: darkGray },
        { group: sampleGroups[0], title: "Item Title: 5", subtitle: "Item Subtitle: 5", description: itemDescription, content: itemContent, backgroundImage: mediumGray }];

如何添加ID?,因为 importancia 选项决定了哪一个有ID。

1 个答案:

答案 0 :(得分:2)

我使用dynamic template bindingid属性的值分配给ListView项。但是,请注意,在@DominicHopton指出的“潜在副本”中,您可能不希望为您的项目分配id

function listViewItemTemplate(item) {
    // data has has information about each item
    var data = item.data._value;

    var itemElement = document.createElement('div');
    if (data.shouldHaveId) { // check whatever condition that you need
        itemElement.id = data.id; // assign an id to your element
    }

    ...

    return {element: itemElement}
}

...

// Then you can assign the template to your listview
youListViewControl.itemTemplate = listViewItemTemplate;