我有3台服务器:
ECPAYSERV2
POSSQLSERVER
ECPAYSERV1
3个数据库
ECPNWEB
ECPNPOS
ECPNDB
和3个表
account
branch
terminal
我还完成了链接服务器:
ECPAYSERV2.ECPNWEB.dbo.account
POSSQLSERVER.ECPNPOS.dbo.branch
ECPAYSERV1.ECPNDB.dbo.terminal
应该看到的字段是以下
AccountID = ECPAYSERV2.ECPNWEB.dbo.account.(accntid)
BranchID = ECPAYSERV2.ECPNWEB.dbo.branch.(branchid)
TID = ECPAYSERV1.ECPNDB.dbo.terminal.(TID)
Store # = POSSQLSERVER.ECPNPOS.dbo.branch.(Storeno)
Store name = ECPAYSERV2.ECPNWEB.dbo.account.(accountholder)
Branch name = ECPAYSERV2.ECPNWEB.dbo.brachn.(branchname) , POSSQLSERVER.ECPNPOS.dbo.branch.(branchname) , ECPAYSERV1.ECPNDB.dbo.terminal.(retail_store_code)
用parethesis括起来的数据是列。
要清楚所有这些是表格中的列..
表:帐户
|Accntid|managedby|Accountholder|Description|AccountType|ContactPerson|ContactNumber|EmailAddress|
表:分支
|BranchID|BranchName|AccountID|StoreNo|Description|Status|
表:终端
|TerminalID|TID|retail_store_code|t_distributor_code|
我想要的只是使用正确的数据获取此输出..
|accntid|accountholder|tid|storeno|branchname|branchid|
这是我尝试但没有得到正确的输出
SELECT account.accntid,account.accountholder,terminal.tid,branch.storeno,branch.branchname,branch1.branchid
FROM ECPAYSERV2.ECPNWEB.dbo.account as account
INNER JOIN POSSQLSERVER.ECPNPOS.dbo.branch as branch
ON account.accntid=branch.branchid
INNER JOIN ECPAYSERV2.ECPNWEB.dbo.branch as branch1
ON account.accntid=branch1.branchid
INNER JOIN ECPAYSERV1.ECPNDB.dbo.terminal as terminal
ON account.accntid=terminal.tid
请帮我解决这件事谢谢:(
答案 0 :(得分:1)
SELECT
account.accntid, account.accountholder, terminal.tid, branch.storeno, branch.branchname, branch1.branchid
FROM
ECPAYSERV2.ECPNWEB.dbo.account as account
INNER JOIN POSSQLSERVER.ECPNPOS.dbo.branch as branch
ON account.accntid=branch.AccountID
INNER JOIN ECPAYSERV2.ECPNWEB.dbo.branch as branch1
ON account.accntid=branch1.AccountID
INNER JOIN ECPAYSERV1.ECPNDB.dbo.terminal as terminal
ON account.accntid=terminal.???
???是不正确的,但不清楚终端的哪一列是帐户的FK。