Question

“选择pck.id，pck.name，deb.last_time（选择id，来自dp_package的名称，其中名称如％s限制％s，％s）作为pck left join（从dp_deb中选择package_id，last_time，其中id为（通过package_id从dp_deb group中选择max（id）））作为pck.id = deb.package_id上的deb“％（关键字，开始，限制）

Answer 1

假设模型已定义： Base = declarative_base（）

class Package(Base):
    __tablename__ = 'db_package'
    id = Column(Integer, primary_key=True)
    name = Column(String)
    def __init__(self, name):
        self.name = name

class Deb(Base):
    __tablename__ = 'db_deb'
    id = Column(Integer, primary_key=True)
    package_id = Column(Integer, ForeignKey('db_package.id'))
    name = Column(String)
    last_time = Column(DateTime)
    def __init__(self, name, last_time):
        self.name = name
        self.last_time = last_time

    packages = relationship(Package, backref="debs")

下面的代码应该产生相同的结果（尽管SQL查询不同，其中一个subquery被简单的LEFT OUTER JOIN替换：

# query parameters
keyword, start, limit = 'xxx', 1, 3

# subquery for the last_time
sq2h = session.query(Deb.package_id, func.max(Deb.id).label("max_id")).group_by(Deb.id).subquery("max_deb")
sq2 = (session.query(Deb.package_id, Deb.last_time).
        join(sq2h, Deb.id == sq2h.c.max_id))
sq2 = sq2.subquery("deb")

qry = (session.query(Package.id, Package.name, sq2.c.last_time).
        outerjoin(sq2, sq2.c.package_id == Package.id).
        filter(Package.name.contains(keyword))
        )[start:(start + limit)]
print qry

为SQL生成此SQLite：

SELECT  db_package.id AS db_package_id, 
        db_package.name AS db_package_name, 
        deb.last_time AS deb_last_time
FROM    db_package 
LEFT OUTER JOIN(SELECT  db_deb.package_id AS package_id, db_deb.last_time AS last_time
                FROM    db_deb 
                JOIN   (SELECT  db_deb.package_id AS package_id, 
                                max(db_deb.id) AS max_id
                        FROM    db_deb 
                        GROUP BY db_deb.id
                       ) AS max_deb 
                  ON db_deb.id = max_deb.max_id
        ) AS deb 
    ON  deb.package_id = db_package.id
WHERE   db_package.name LIKE '%%' || ? || '%%'
LIMIT ? OFFSET ?

('xxx', 3, 1)

如何在sqlalchemy中生成这个sql，我很努力，但不知道该怎么做

1 个答案: