代码的以下部分不起作用,因为每个单词的获胜/丢失计数持续增加1,有时我会得到一个带字符串长度的nullpointerexception。此外,虽然玩家应该获得7次尝试(int no),但有时他会获得更多,有时更少。字符串取自文本文件“Hangeng.txt”。整个游戏位于按键监听器内的键盘键控侦听器内。有关如何安排游戏布局以避免错误的任何提示都是受欢迎的,因为我只是开始使用swing和gui的东西。
public class test{
static int won = 0;
static int lost = 0;
static String key = "";
static String word = null;
static int no = 0;
static StringBuffer toguess;
public static void main(String[] args) throws IOException{
JFrame frame = new JFrame();
frame.setLayout(new GridLayout(3,1));
JPanel panel1 = new JPanel();
JPanel panel2 = new JPanel();
JPanel panel3 = new JPanel();
JButton button = new JButton();
JLabel label = new JLabel();
JLabel label2 = new JLabel();
panel1.add(label);
panel2.add(button);
panel3.add(label2);
frame.setSize(800,600);
frame.add(panel1);
frame.add(panel2);
frame.add(panel3);
frame.setVisible(true);
//the button that starts the game or gets a new word
button.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
frame.requestFocus();
no = 0;
label2.setText("won " + won + ", lost " + lost);
button.setText("Next");
//get random word from file
BufferedReader reader = null;
try {
reader = new BufferedReader(new FileReader(
"hangeng.txt"));
} catch (FileNotFoundException e1) {
e1.printStackTrace();
}
int lineno = (int) (Math.random() * 100);
for (int i = 0; i < lineno; i++) {
try {
reader.readLine();
} catch (IOException e1) {
e1.printStackTrace();
}
}
try {
word = reader.readLine().replace(" ", "");
} catch (IOException e1) {
e1.printStackTrace();
}
String missing = "";
for (int u = 0; u < (word.length() - 2); u++) {
missing = missing + "*";
}
final String guess = word.charAt(0) + missing
+ word.charAt((word.length() - 1));
toguess = new StringBuffer(guess);
label.setText(toguess.toString());
final ArrayList<String> tried = new ArrayList<String>();
//keylistener that listens to key clicks by the user
frame.addKeyListener(new KeyListener() {
public void keyPressed(KeyEvent arg0) {
}
public void keyReleased(KeyEvent arg0) {
}
public void keyTyped(KeyEvent arg0) {
key = "" + arg0.getKeyChar();
String guessing = null;
boolean k = false;
if ((no < 6)) {
guessing = key;
System.out.println(guessing);
if (!(tried.contains(guessing))) {
tried.add(guessing);
for (int length = 1; length < (guess
.length() - 1); length++) {
if (guessing.equals(String.valueOf(word.charAt(length)))) {
toguess.replace(length,
(length + 1),
String.valueOf(word.charAt(length)));
k = true;
}
}
if (k == true) {
label.setText(toguess.toString());
} else {
no = no + 1;
}
k = false;
}
label.setText(toguess.toString());
if (toguess.toString().equals(word)) {
label.setText("Correct! The word was " + word);
no = 6;
won = won + 1;
}
}
else if ((no == 6)
&& (!(toguess.toString().equals(word)))) {
label.setText("Sorry, but the word was " + word);
lost = lost + 1;
}
}
});
}
});
}
}
答案 0 :(得分:3)
+1所有评论....
添加它们:
不要使用KeyListener
使用KeyAdapter
但是因为您使用Swing而非AWT,您应该使用KeyBinding
进行Swing,例如here。
不要忘记通过Event Dispatch Thread
块在SwingUtiltities.invokeLater(..)
上创建和操作Swing组件,请参阅here了解更多信息。
检查他们以大写字母开头的类命名方案,即test
应为Test
,之后的每个新词应该大写。
请勿在{{1}}上致电setSize
,而是使用适当的JFrame
和/或覆盖LayoutManager
getPreferredSize()
并返回适合其JPanel
的尺寸内容并在添加所有组件后在pack()
实例上调用JFrame
。
另外SSCCE应该可以从复制和粘贴中编译,这不是....即变量需要更改为最终,我没有样本的Hangeng.txt所以无法测试
最后使用@Override注释确保覆盖正确的方法,即
@Override
public void actionPerformed(ActionEvent e) {
}