无法打开SQLite数据库

时间:2012-12-20 02:36:38

标签: c# sqlite windows-8 windows-store-apps sqlite-net

使用此代码:

public void InsertPlatypiRequestedRecord(string PlatypusId, string PlatypusName, DateTime invitationSentLocal)
{
    var db = new SQLiteConnection(SQLitePath);
    {
        db.CreateTable<PlatypiRequested>();
        db.RunInTransaction(() =>
            {
                db.Insert(new PlatypiRequested
                              {
                                  PlatypusId = PlatypusId,
                                  PlatypusName = PlatypusName,
                                  InvitationSentLocal = invitationSentLocal
                              });
                db.Dispose();
            });
    }
}

...我明白了,“ SQLite.SQLiteException未被用户代码处理   的HResult = -2146233088   Message =无法从未打开的数据库创建命令

...但是尝试添加“db.Open()”不起作用,因为显然没有这样的方法。

2 个答案:

答案 0 :(得分:7)

您过早地处理数据库(在事务内部)。最好在“using”语句中包装内容,该语句将处理db连接:

private void InsertPlatypiRequestedRecord(string platypusId, string platypusName, DateTime invitationSentLocal)
{
    using (var db = new SQLiteConnection(SQLitePath))
    {
        db.CreateTable<PlatypiRequested>();
        db.RunInTransaction(() =>
        {
            db.Insert(new PlatypiRequested
            {
                PlatypusId = platypusId,
                PlatypusName = platypusName,
                InvitationSentLocal = invitationSentLocal
            });
        });
    }
}

答案 1 :(得分:1)

string connecString = @"Data Source=D:\SQLite.db;Pooling=true;FailIfMissing=false";       
/*D:\sqlite.db就是sqlite数据库所在的目录,它的名字你可以随便改的*/
SQLiteConnection conn = new SQLiteConnection(connectString); //新建一个连接
conn.Open();  //打开连接
SQLiteCommand cmd = conn.CreateCommand();

cmd.CommandText = "select * from orders";   //数据库中要事先有个orders表

cmd.CommandType = CommandType.Text;
using (SQLiteDataReader reader = cmd.ExecuteReader())
{
   while (reader.Read())
                Console.WriteLine( reader[0].ToString());
}

您可以下载System.Data.SQLite.dll here

这是csharp connect sqlite

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