Question

我有两个逗号分隔NSString和＆amp;我想从第一个字符串中删除相似的字符。

ex. str1 = 0,1,2,3
    str2 = 1,2.
    output -> str1 = 0,3 and str2 = 1,2.

我有一个选项，用数组中的逗号分隔值分隔两个字符串。但它需要两个NSArray＆amp;应用loop然后删除常用元素，但这是非常繁琐的工作。所以我想要一些简单的＆amp;避免循环的适当解决方案。

请帮助我解决这个问题。

Answer 1

试试这个：

不需要循环!!!

您已获得所有必需的API。

NSString *str1=@"0,1,2,3";
NSString *str2=@"1,2";

NSMutableArray *arr1=[[NSMutableArray alloc]initWithArray:[str1 componentsSeparatedByString:@","]];

[arr1 removeObjectsInArray:[str2 componentsSeparatedByString:@","]];
NSLog(@"arr1 %@",arr1);
/*
NSMutableString *finalString=[NSMutableString new];

for (NSInteger i=0; i<[arr1 count]; i++) {
    NSString *str=[arr1 objectAtIndex:i];

    [finalString appendString:str];
    if (i!=[arr1 count]-1) {
      [finalString appendString:@","];  
    }
}
*/
NSString *finalString=[arr1 componentsJoinedByString:@","];
NSLog(@"finalString %@",finalString);

Answer 2

那样的东西？

 NSString *string = @"0,1,2,3";
 NSPredicate *predicate = [NSPredicate predicateWithFormat:@"self like '1' OR self like '2'"];
 NSLog(@"%@",[[string componentsSeparatedByString:@","] filteredArrayUsingPredicate:predicate]);

Answer 3

    id str1=@"aa,ab,ac,cd,ce,cf";
    id str2=@"aa,ac,cd,cf";
    //no ab and no ce

    id cmps1 = [str1 componentsSeparatedByString:@","];
    id cmps2 = [str2 componentsSeparatedByString:@","];        

    NSPredicate *predicate = [NSPredicate predicateWithFormat:@"NOT SELF IN %@", cmps2];
    NSArray *final = [cmps1 filteredArrayUsingPredicate:predicate]; 
    id str = [final componentsJoinedByString:@","];
    NSLog(@"%@", str);

比较两个字符串并删除常用元素

3 个答案: