如何使用全名创建CultureInfo实例或将全名转换为CultureInfo代码？

Question

无论如何使用完整的displayname：

创建cultureInfo对象的实例

CultureInfo userCulture = new CultureInfo("Japanese (Japan)");

或将完整的显示名称转换为文化代码：

toCultureCode("Japanese (Japan)"); 

会返回"ja-JP"

Answer 1

没有内置方法可以通过它的英文名称来获取文化，所以你可以写一个：

public static CultureInfo getCultureByEnglishName(String englishName)
{
    // create an array of CultureInfo to hold all the cultures found, 
    // these include the users local culture, and all the
    // cultures installed with the .Net Framework
    CultureInfo[] cultures = CultureInfo.GetCultures(CultureTypes.AllCultures & ~CultureTypes.NeutralCultures);
    // get culture by it's english name 
    var culture = cultures.FirstOrDefault(c => 
        c.EnglishName.Equals(englishName, StringComparison.InvariantCultureIgnoreCase));
    return culture;
}

DEMO

toCultureCode为ToString：

String name = "Japanese (Japan)";
CultureInfo japanCulture = getCultureByEnglishName(name);
Console.Write(japanCulture.ToString()); // -> "ja-JP"

Answer 2

您可以使用Linq

using System.Linq;

CultureInfo culture = CultureInfo.GetCultures(CultureTypes.AllCultures).FirstOrDefault(c => c.DisplayName == "Japanese (Japan)");