Question

我有一个表视图，UIView.Table视图单元格中有带image的单元格。我想在选择perticuler单元格时，相应的图像应出现在UIView中的“UIImage对象”中。

在表格视图中：

//I'm getting temp image as following(in my "cellForRowAtIndexPath" method)
  if(indexPath.row == 0)
    {
        [[cell imageView]setImage:[UIImage imageNamed:@"greekChickenSalad.png"]];
        tempImage = [UIImage imageNamed:@"greekChickenSalad.png"];
    }

 -(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([segue.identifier isEqualToString:@"SubRecipeDescriptionSegue"])
{
     RecipeDescriptionViewController *rdVC;
    rdVC = segue.destinationViewController;
    rdVC.parentIndexRDVC = descriptionIndexPath;
    rdVC.DescriptionLabel = (UILabel*)subRecipeSelected;
    rdVC.image = tempImage;

}

}

在UIView中，LoadView方法添加如下图像：

NSData *imageDataString = UIImagePNGRepresentation(image);
NSString *imageNamedContent = [[NSString alloc]initWithBytes:[imageDataString bytes] length:[imageDataString length] encoding:NSASCIIStringEncoding];
UIImage *image1 = [UIImage imageNamed:imageNamedContent];
UIImageView *imageView = [[UIImageView alloc]initWithImage:image1];
imageView.frame = CGRectMake(30,30, 250, 100);
[self.view addSubview:imageView];

在上面的代码中，我将图像转换为NSString（[UIImage imageNamed：imageNamedContent]） - 这是正确的吗？

如果没有，我该怎么做？

注意：如果我将表格单元格的文本传递给UIView中的标签，Segue工作正常。

希望我的问题很明确。

Answer 1

变化：

NSData *imageDataString = UIImagePNGRepresentation(image);
NSString *imageNamedContent = [[NSString alloc]initWithBytes:[imageDataString bytes] length:[imageDataString length] encoding:NSASCIIStringEncoding];
UIImage *image1 = [UIImage imageNamed:imageNamedContent];
UIImageView *imageView = [[UIImageView alloc]initWithImage:image1];

分为：

UIImageView *imageView = [[UIImageView alloc]initWithImage:image];

您还需要获取当前单元格的图像并使用performSegueWithIdentifier发送它：

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
    UITableViewCell *cell = [tableView cellForRowAtIndexPath:indexPath];
    [self performSegueWithIdentifier:@"SubRecipeDescriptionSegue" sender:cell.imageView.image];
}

然后您需要更新prepareForSegue方法：

-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
    if ([segue.identifier isEqualToString:@"SubRecipeDescriptionSegue"])
    {
        UIImage *selectedImage = (UIImage*)sender;

        RecipeDescriptionViewController *rdVC;
        rdVC = segue.destinationViewController;
        rdVC.parentIndexRDVC = descriptionIndexPath;
        rdVC.DescriptionLabel = (UILabel*)subRecipeSelected;
        rdVC.image = selectedImage;
    }
}

如何使用segue将图像从表格单元格传递到UIView中的UIImage对象？

1 个答案: