我们正在寻找使用CSS来创建如下所示的有序列表:
A.
A.1
A.2
B.
C.
C.1
C.2
C.2.1
C.2.2
你会如何在孩子中包含这样的父索引?
答案 0 :(得分:5)
您应该使用CSS counters W3C specs( as @Zeta )指出,但这是一种处理多个嵌套和拉丁计数器的方法。
ol{
list-style: none;
}
ol.roman{
counter-reset: roman;
}
ol.roman > li:before{
counter-increment: roman;
content: counter(roman, upper-latin)".";
padding-right:5px;
}
ol.roman li ol{
counter-reset: inner;
}
ol.roman ol li:before{
counter-increment: inner;
content: counter(roman, upper-latin)"."counters(inner,'.');
padding-right:5px;
}
演示
答案 1 :(得分:3)
您需要使用CSS counters。
CSS:
ol {
counter-reset: section; /* Creates a new instance of the
section counter with each ol
element */
list-style-type: none;
}
li:before {
counter-increment: section; /* Increments only this instance
of the section counter */
content: counters(section, ".") " "; /* Adds the value of all instances
of the section counter separated
by a ".". */
}
HTML:
<ol>
<li>Entry
<li>Entry
<li>Entry with subentries
<ol>
<li>Entry
<li>Entry
<li>Entry
<li>Entry
</ol>
<li>Entry
<li>Entry
<li>Entry with subentries
<ol>
<li>Entry
<li>Entry
<li>Entry
<li>Entry
</ol>
</ol>