我试图以编程方式将WebView插入我的代码中

时间:2012-12-11 06:47:19

标签: java android user-interface view

我有一个附有点击监听器的表面视图。

当我点击它时,它将它缩小到宽度的一半和高度的一半......并通过以下方式将它放在右下角:

RelativeLayout.LayoutParams rlp = new RelativeLayout.LayoutParams(  
    getWindowManager().getDefaultDisplay().getWidth()/2,
    getWindowManager().getDefaultDisplay().getHeight()/2    
);
rlp.setMargins(
  getWindowManager().getDefaultDisplay().getWidth()/2,    
  getWindowManager().getDefaultDisplay().getHeight()/2, 
  0, 
  0);

它按预期工作,但我想在它后面动态地放置webView。

我试过了:

WebView wv = makeWebView();
//makeWebView(); is a method of my mainActivity, which simple does.
private Webview makeWebView(){ return new WebView(this); }

我似乎无法让它落后于其他一切。我做错了吗?

我的XML:

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/RR1"
android:layout_width="match_parent"
android:layout_height="match_parent"
tools:context=".MainActivity" >

<LinearLayout
    android:id="@+id/LL1"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >

    <SurfaceView
        android:id="@+id/surfaceView1"
        android:layout_width="match_parent"
        android:layout_height="match_parent" />

</LinearLayout>

</RelativeLayout>

我的MainActivity:

package com.example.testfortim;

import android.os.Bundle;
import android.app.Activity;
import android.graphics.Color;
import android.view.Gravity;
import android.view.Menu;
import android.view.SurfaceView;
import android.view.View;
import android.view.View.OnClickListener;
import android.webkit.WebView;
import android.widget.LinearLayout;
import android.widget.RelativeLayout;

public class MainActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    //SurfaceView sv = new SurfaceView();
    SurfaceView sv = (SurfaceView)findViewById(R.id.surfaceView1);
    sv.setOnClickListener(new OnClickListener(){

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            LinearLayout ll = (LinearLayout)findViewById(R.id.LL1);
            //LinearLayout.LayoutParams llp = (LinearLayout.LayoutParams)ll.getLayoutParams();
            //RelativeLayout.LayoutParams rlp = new RelativeLayout.LayoutParams(ll.getLayoutParams().width/2,ll.getLayoutParams().height/2);//(RelativeLayout.LayoutParams)ll.getLayoutParams();
            RelativeLayout.LayoutParams rlp = new RelativeLayout.LayoutParams(
                    getWindowManager().getDefaultDisplay().getWidth()/2, 
                    getWindowManager().getDefaultDisplay().getHeight()/2
                    );
            rlp.setMargins(getWindowManager().getDefaultDisplay().getWidth()/2, getWindowManager().getDefaultDisplay().getHeight()/2, 0, 0);
            ll.setLayoutParams(rlp);

            WebView wv = makeWebView();
            //wv.setBackgroundColor(0);
            //wv.setBackgroundResource(R.color.Blue);
            //wv.setBackgroundResource(Color.BLUE);
            wv.loadData("<html><body>TEST</body></html>", "text/html", "utf-8");
            RelativeLayout rl = (RelativeLayout)findViewById(R.id.RR1);
            //rl.addView(wv);

            //ll.addView(wv);


        }

    });

}

protected WebView makeWebView() {
    return new WebView(this);
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.activity_main, menu);
    return true;
}

}

我调整了线性布局的大小并将其移动了,因此需要将Webview放置在RR1中的某个位置,而不是我收集的内容。我正在查看各种文档,它或者不是通过随机性寻找或接受的,我只是没有把握它。

您是否了解如何实现这一目标?

作为旁注:我不知道为什么onCreateOptionMenu方法存在。我不打算使用它,并且会最终删除它。

1 个答案:

答案 0 :(得分:4)

试试rl.addView(wv, 0); 会做的伎俩:)