我知道我的代码有点乱，但我会尽量详细说明。代码正在创建一个TicTacToe游戏。我正在使用数组来创建游戏板，即gameBoard（）。用户总是X而计算机总是O.我已创建if语句的用户输入和计算机输入，不同的是，计算机从java.util.Random获取其编号。 if语句获取用户的输入并在指定的板上打印X，与计算机相同。这里的问题是当随机生成器选择X已经存在的空间时，它重叠，反之亦然。我需要程序秘密告诉计算机生成另一个随机数。如果你能提供帮助就会很棒。对不起，有大的描述。
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
import java.util.Random;
public class TicTacToeGame {
static String arrayPicture[][]; //Array is universal so we can include it into any method
static int userInput;
static boolean validInput = false;
static String name;
public static void main (String[] args) throws IOException {
System.out.println ("Please enter your name:");
name = gameStart("");
arrayPicture = new String [13][13];
for (int i = 0; i < 13; i ++) {
for (int j = 0; j < 13; j ++) {
arrayPicture [i][j] = " "; //Print spaces into the array
}
}
while (validInput == false) {
validX();
cpuPlacement();
System.out.println ("Computer, please enter your number");
validInput = false;
}
}//main
public static void verticalLine (int x1, int y1, int x2) {
for (int k = x1; k < x2; k ++) {
arrayPicture [y1][k] = "|"; //if y1 and k are present, print a vertical line in the array
}
}//verticalLine
public static void horizontalLine (int x1, int y1, int x2) {
for (int k = x1; k < x2; k ++) {
arrayPicture [y1][k] = "-"; //if y1 and k are present, print a dash in the array
}
}//horizontalLine
public static void printArray () {
for (int i = 0; i < 13; i ++) {
for (int j = 0; j < 13; j ++) {
System.out.print (arrayPicture[i][j]);
}
System.out.println();
}
}//printArray
public static String gameStart (String input) throws IOException {
boolean validInput = false;
BufferedReader userInput = new BufferedReader (new InputStreamReader(System.in));
while (validInput == false) {
input = userInput.readLine();
validInput = true;
System.out.println ("The name of the game is TicTacToe, you will always be the letter X.");
System.out.println ("Please choose the coordinates you wish. The coordinates are where your X will be placed on the game board.");
}
return input;
}
public static void validX () throws IOException {
gameBoard();
String input = null;
System.out.println (name + ", please enter your number");
try {
BufferedReader columnNumber = new BufferedReader (new InputStreamReader(System.in));//BufferedReader variable where the user will input their answer
input = columnNumber.readLine();
userInput = Integer.parseInt (input);
validInput = true;
userPlacement();
//If an exception is present, the try sends it to catch.
//Ex. If the user in\puts "bob has a cat" the try will find an exception and immediately send it to the catch statement
}
catch (NumberFormatException ex) {
System.out.println ("Invalid input, please enter a number.");
validInput = false;
}
if (userInput == 1) {
userInputX (2, 2, 3);
}
else if (userInput == 2) {
userInputX (6, 2, 7);
}
else if (userInput == 3) {
userInputX (10, 2, 11);
}
else if (userInput == 4) {
userInputX (2, 6, 3);
}
else if (userInput == 5) {
userInputX (6, 6, 7);
}
else if (userInput == 6) {
userInputX (10, 6, 11);
}
else if (userInput == 7) {
userInputX (2, 10, 3);
}
else if (userInput == 8) {
userInputX (6, 10, 7);
}
else if (userInput == 9) {
userInputX (10, 10, 11);
}
}
public static void cpuinputO (int x1, int y1, int x2) throws IOException {
gameBoard();
for (int k = x1; k < x2; k ++) {
arrayPicture [y1][k] = "O"; //if y1 and k are present, print a dash in the array
}
}
public static void userInputX (int x1, int y1, int x2) {
for (int k = x1; k < x2; k ++) {
arrayPicture [y1][k] = "X"; //if y1 and k are present, print a dash in the array
}
}
public static void userPlacement () throws IOException {
if (userInput == 1) {
userInputX (2, 2, 3);
}
else if (userInput == 2) {
userInputX (6, 2, 7);
}
else if (userInput == 3) {
userInputX (10, 2, 11);
}
else if (userInput == 4) {
userInputX (2, 6, 3);
}
else if (userInput == 5) {
userInputX (6, 6, 7);
}
else if (userInput == 6) {
userInputX (10, 6, 11);
}
else if (userInput == 7) {
userInputX (2, 10, 3);
}
else if (userInput == 8) {
userInputX (6, 10, 7);
}
else if (userInput == 9) {
userInputX (10, 10, 11);
}
}
public static void cpuPlacement () throws IOException {
Random random = new Random();
int cpuCoordinates = random.nextInt(10);
System.out.println (cpuCoordinates);
boolean validInput0 = false;
if (validInput0 == true) {
if (cpuCoordinates < 1) {
validInput0 = false;
}
}
else if (cpuCoordinates == 1) {
cpuinputO (2, 2, 3);
}
else if (cpuCoordinates == 2) {
cpuinputO (6, 2, 7);
}
else if (cpuCoordinates == 3) {
cpuinputO (10, 2, 11);
}
else if (cpuCoordinates == 4) {
cpuinputO (2, 6, 3);
}
else if (cpuCoordinates == 5) {
cpuinputO (6, 6, 7);
}
else if (cpuCoordinates == 6) {
cpuinputO (10, 6, 11);
}
else if (cpuCoordinates == 7) {
cpuinputO (2, 10, 3);
}
else if (cpuCoordinates == 8) {
cpuinputO (6, 10, 7);
}
else if (cpuCoordinates == 9) {
cpuinputO (10, 10, 11);
}
}
public static void gameBoard () throws IOException {
System.out.println (" ");
horizontalLine (1, 0, 4); horizontalLine (5, 0, 8); horizontalLine (9, 0, 12);
verticalLine (0, 1, 1); verticalLine (4, 1, 5); verticalLine (8, 1, 9); verticalLine (12, 1, 13);
verticalLine (0, 2, 1); verticalLine (4, 2, 5); verticalLine (8, 2, 9); verticalLine (12, 2, 13);
verticalLine (0, 3, 1); verticalLine (4, 3, 5); verticalLine (8, 3, 9); verticalLine (12, 3, 13);
horizontalLine (1, 4, 4); horizontalLine (5, 4, 8); horizontalLine (9, 4, 12);
verticalLine (0, 5, 1); verticalLine (4, 5, 5); verticalLine (8, 5, 9); verticalLine (12, 5, 13);
verticalLine (0, 6, 1); verticalLine (4, 6, 5); verticalLine (8, 6, 9); verticalLine (12, 6, 13);
verticalLine (0, 7, 1); verticalLine (4, 7, 5); verticalLine (8, 7, 9); verticalLine (12, 7, 13);
horizontalLine (1, 8, 4); horizontalLine (5, 8, 8); horizontalLine (9, 8, 12);
verticalLine (0, 9, 1); verticalLine (4, 9, 5); verticalLine (8, 9, 9); verticalLine (12, 9, 13);
verticalLine (0, 10, 1); verticalLine (4, 10, 5); verticalLine (8, 10, 9); verticalLine (12, 10, 13);
verticalLine (0, 11, 1); verticalLine (4, 11, 5); verticalLine (8, 11, 9); verticalLine (12, 11, 13);
horizontalLine (1, 12, 4); horizontalLine (5, 12, 8); horizontalLine (9, 12, 12);
printArray ();
}//gameBoard
}//public class
答案 0 :(得分：1)
我不太确定你的代码中发生了什么（你为什么骑自行车穿过Tic-Tac-Toe的13×13阵列？）但这应该是一个简单的解决方法。最简单的解决方法是在CPU放置代码周围添加while循环，而不是当前的if / else-if语句。 （if / else-ifs应该在while循环中。）当找到有效的位置时，
while(validInput0==false){
if(cpuCoordinates == 1){
if(squareOneOwner == null){
squareOneOwner = "CPU"
validInput0 = true;
}
}else if(...){
...
}
if(validInput0 == false){
cpuCoordinates = random.nextInt(10);
}
}
等。这使您可以检查计算机的目标是否正方形，并且只有在它当前为空时才声明它。它需要在其他地方进行一些更改，但它们很简单。如果先前的尝试无效，则最后一个if语句将重新滚动到下一个周期。
答案 1 :(得分：1)
我认为您的代码需要进行一些重组。
在我看来，你应该将cpu和player制作的条目存储到2d int数组中。计算机可以由1 s表示，玩家可以由2表示。空方块由0 s表示。
然后，您可以使用嵌套的for循环遍历此数组以绘制游戏板。
int[][] game_board = new int[3][3]
for(int i = 0; i < 3; i++)
{
for(int j = 0; j < 3; j++)
{
if(game_board[i][j] == 1)
...code to print an X...
if(game_board[i][j] == 2)
...code to print an O...
if(game_board[i][j] == 0)
...code to print some spaces...
...code to print a vertical line...
}
...code to print a horizontal line...
}
当计算机或播放器做出选择时，您只需检查该地点的game_board是否为0，如果不是，则必须另行选择。
choice_x = ...user or computer chooses an x location...
choice_y = ...user or computer chooses a y location...
if(game_board[choice_x][choice_y] != 0)
{
...choose again...
}
else
{
if( player is choosing )
game_board[choice_x][choice_y] = 1
if( computer is choosing )
game_board[choice_x][choice_y] = 0
}