Question

我有一个字符串：

mydata
'POINT (558750.3267372231900000 6361788.0628051758000000)'

我希望使用代码保存方式将数组转换为

(g, (x,y))

其中：

g = geometry (POINT)
x = coordinates x
y = coordinates y

我正在使用

mydata.split(" ")
['POINT', '(558750.3267372231900000', '6361788.0628051758000000)']

但之后我需要使用几个代码行来获取x和y

Answer 1

一步一步：

>>> s = 'POINT (558750.3267372231900000 6361788.0628051758000000)'
>>> word, points = s.split(None, 1)
>>> word
'POINT'
>>> points
'(558750.3267372231900000 6361788.0628051758000000)'
>>> points = points.strip('()').split()
>>> points
['558750.3267372231900000', '6361788.0628051758000000']
>>> x, y = (float(i) for i in points)
>>> x
558750.3267372232
>>> y
6361788.062805176

Answer 2

正则表达式可以让你在这里打字：

In [1]: import re

In [2]: def nice_tuple(s):                                                    
    g, x, y, _ = re.split(' ?[()]?', s)
    return g, tuple(map(float, (x, y)))
   ...: 

In [3]: nice_tuple('POINT (558750.3267372231900000 6361788.0628051758000000)')
Out[3]: ('POINT', (558750.3267372232, 6361788.062805176))

Answer 3

如果您的数据始终采用相同格式，则很容易：

>>> def parse_data(d):
    geom, xs, ys = d.split()
    return (geom, (float(xs[1:]), float(ys[:-1])))

>>> mydata
'POINT (558750.3267372231900000 6361788.0628051758000000)'
>>> parse_data(mydata)
('POINT', (558750.32673722319, 6361788.0628051758))

Answer 4

v = mydata.split()
g = v[0]
x = float(v[1].strip('('))
y = float(v[2].strip(')'))
(g, (x, y))

代码保存是，优雅不是那么多

Answer 5

使用regex：

In [59]: g,[x,y]=re.findall(r"[A-Za-z]+",mydata)[0],
                       [float(x) for x in re.findall(r"[\d+.]+",mydata)]

In [60]: g
Out[60]: 'POINT'

In [61]: x
Out[61]: 558750.3267372232

In [62]: y
Out[62]: 6361788.062805176

使用str.strip()和str.split()：

In [35]: mydata='POINT (558750.3267372231900000 6361788.0628051758000000)'

In [39]: data=mydata.split(None,1)

In [40]: data
Out[40]: ['POINT', '(558750.3267372231900000 6361788.0628051758000000)']

In [41]: g,[x,y]=data[0], map(lambda x: float(x.strip("()")), data[1].split())

In [42]: g,x,y
Out[42]: ('POINT', 558750.3267372232, 6361788.062805176)

Answer 6

found = re.match(r'([a-zA-Z]*) \(([0-9\.]*) ([0-9\.]*)\)', mydata)
found.group(1), (float(found.group(2)), float(found.group(3)))

这可能是最短的，不了解优雅。

Answer 7

我会使用.translate和.split：

In [126]: mydata = 'POINT (558750.3267372231900000 6361788.0628051758000000)'

In [127]: mysplitdata = mydata.translate(None, '()').split()

In [128]: mysplitdata
Out[128]: ['POINT', '558750.3267372231900000', '6361788.0628051758000000']

In [129]: g,x,y = mysplitdata[0],float(mysplitdata[1]),float(mysplitdata[2])

In [130]: outdata = (g, (x,y))

In [131]: outdata
Out[131]: ('POINT', (558750.32673722319, 6361788.0628051758))

Answer 8

最近我在python中创建了一个应用程序，我做了几乎相同的事情。这是我创建的用于解析wkt文件的类。

link

希望你觉得它很有用。有关用法，请参阅第136行。您也可以使用此类来读取Linestrings和Multilinestrings。

Python：在列表中拆分字符串的优雅和代码保存方式

8 个答案: