输入1
1 886817 2 122 C :0.983607 T :0.0163934
1 886817 3 123 C :2.111 CATTTT :1.11
输入2
1 886817 rs10465241 C T 100 PASS AC = 1573;
1 886817 。 C CATTTT 874通过AVGPOST = 0.9884;
输出
1 886817 rs10465241 C T 100 PASS AC = 1573; REF = 0.983607; ALT = 0.0163934
1 886817。 C CATTTT 874通过AVGPOST = 0.9884; REF = 2.111; ALT = 1.11
根据粗体列匹配生成输出.REF和ALT值正在添加
答案 0 :(得分:1)
我想我刚刚回答了this个问题。然而,一些细微的变化:
awk 'FNR==NR { split($5,a,":"); split($6,b,":"); c[$1,$2,a[1],b[1]]="REF=" a[2] ";ALT=" b[2]; next } ($1,$2,$4,$5) in c { print $0 c[$1,$2,$4,$5] }' file1 file2
结果:
1 886817 rs10465241 C T 100 PASS AC=1573;REF=0.983607;ALT=0.0163934
1 886817 . C CATTTT 874 PASS AVGPOST=0.9884;REF=2.111;ALT=1.11