Question

我有以下jpa条件查询：

    CriteriaBuilder cb = em.getCriteriaBuilder();
    CriteriaQuery<Company> cq = cb.createQuery(Company.class);
    Root<Company> root = cq.from(Company.class);
    cq.select(root);

    Subquery<String> sq = cq.subquery(String.class);
    Root<Employee> subroot = sq.from(Employee.class);
    sq.select(subroot.get(Employee_.lastName));

    Predicate typePredicate = cb.equal(subroot.get(Employee_.lastName), "Doe");

    Predicate correlatePredicate = cb.equal(root.get(Company_.employees), subroot);
    sq.where(cb.and(typePredicate, correlatePredicate));
    cq.where(cb.exists(sq));


    TypedQuery<Company> typedQuery = em.createQuery(cq);
    List<Company> companies = typedQuery.getResultList();

Eclipselink生成以下SQL：

    SELECT t0.ID, ... FROM COMPANY t0 
    WHERE EXISTS (SELECT t1.LASTNAME FROM EMPLOYEES t2, EMPLOYEES t1 
                  WHERE (((t1.LASTNAME = ?) AND (t1.ID = t2.ID)) 
                  AND (t2.COMPANY_ID = t0.ID)))

正如您所看到的，表EMPLOYEES上有一个不必要的连接。我如何摆脱这种加入？

Answer 1

您似乎不需要查询的子查询，只需要一个连接即可，

http://en.wikibooks.org/wiki/Java_Persistence/Criteria#Join

否则，您使用的是哪个版本？你能试试EclipseLink 2.4吗？

如果仍有副本，请记录错误并投票支持。

您可以使用逆ManyToOne而不是OneToMany（即root == subroot.get（“company”））。

在2.4中尝试JPQL，是否优化了连接？

不必要的加入jpa子查询

1 个答案: