Question

我使用AsyncTask从net获取数据并在Textview中显示，这是我的代码

public class PatientAssistant extends Activity {

    private TextView txtTemp,txtHuminity;


    @Override
    protected void onCreate(Bundle savedInstanceState) {

        super.onCreate(savedInstanceState);
        setContentView(R.layout.patient_assistant);
        AppPreferences pref=new AppPreferences(this);

        TextView textCity=(TextView)findViewById(R.id.txtCity);

        txtTemp=(TextView)findViewById(R.id.txtTemp);
        txtHuminity=(TextView)findViewById(R.id.txtHumidity);

        textCity.setText(pref.getCity());

        String city=(String) textCity.getText();

        CallWeatherAsync cwa=new CallWeatherAsync(this,txtTemp,txtHuminity);

        cwa.execute(city);


        Button btnSend=(Button)findViewById(R.id.btnSend);
        btnSend.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View v) {
                //TODO send report

            }
        });
    }

    private class CallWeatherAsync extends AsyncTask<String, Void, WeatherInfo> {

        private PatientAssistant _activity;
        private TextView txtT,txtH;
        public CallWeatherAsync(PatientAssistant activity,TextView txtTmp,TextView txthum)
        {
            _activity=activity;
            txtT=txtTmp;
            txthum=txtH;
        }
        @Override
        protected WeatherInfo doInBackground(String... params) {

            YahooWeatherUtils yahooWeatherUtils = YahooWeatherUtils.getInstance();

            WeatherInfo weatherInfo = yahooWeatherUtils.queryYahooWeather(_activity.getApplicationContext(), params[0]);
            return weatherInfo;
        }
        @Override
        protected void onPostExecute(WeatherInfo result) {

            txtT.setText(result.getCurrentTempC());
            txtH.setText(result.getAtmosphereHumidity());
        }

    }

}

但这会抛出 Resources $ NotFoundException !!!

12-02 00:39:06.383: E/AndroidRuntime(4035): android.content.res.Resources$NotFoundException: String resource ID #0xc 12-02 00:39:06.383: E/AndroidRuntime(4035): at android.content.res.Resources.getText(Resources.java:247) 12-02 00:39:06.383: E/AndroidRuntime(4035): at android.widget.TextView.setText(TextView.java:3473) 12-02 00:39:06.383: E/AndroidRuntime(4035): at com.assitant.patient.PatientAssistant$CallWeatherAsync.onPostExecute(PatientAssistant.java:116) 12-02 00:39:06.383: E/AndroidRuntime(4035): at com.assitant.patient.PatientAssistant$CallWeatherAsync.onPostExecute

我怎么能这样做？

Answer 1

盲目的猜测是：

txtT.setText(result.getCurrentTempC());
txtH.setText(result.getAtmosphereHumidity());

返回int而不是string。如果是int则将其视为资源ID。这应该有效：

txtT.setText( "" + result.getCurrentTempC());
txtH.setText( "" + result.getAtmosphereHumidity());

Answer 2

干杯！，你的问题应该是的 txthum = txtH; 它应该是 txtH = txthum;

Answer 3

您不要在私有类中设置TextView。由于您将2个TextView设置为PatientAssistant类的全局变量，因此您应该直接在私有AsyncClass中使用它们。

使用AsyncTask从Internet更新Textview

3 个答案: