我正在尝试构建一个发送文件的客户端/服务器应用程序,但我遇到了较大文件的问题。我正在使用BufferedInputStream从文件读取信息,并使用OutputStream写入套接字。我有一个循环,从文件读取1 KB,然后发送它,这适用于前25个循环然后崩溃与套接字写入错误。有任何想法吗?这是代码。
客户端
import java.io.*;
import java.net.Socket;
import java.util.logging.Level;
import java.util.logging.Logger;
public class TCPClient
{
public static void main(String[] args)
{
/*Variables*/
int serverPort = 8899;
String ip = "localhost";
File myFile = new File("GeneratedFile.txt"); //fileToBeSent.txt
System.out.println(myFile.length());
try
{
/*Connect to Server*/
Socket sock = new Socket(ip, serverPort);
System.out.println("Connection Made");
/*Create Streams*/
FileInputStream fis = new FileInputStream(myFile);
BufferedInputStream bis = new BufferedInputStream(fis);
OutputStream clientOutput = sock.getOutputStream();
/*This is the old code for transfer*/
/*Create Byte Array
byte[] myByteArray = new byte[(int) myFile.length()]; //was 1024
/*Send File
bis.read(myByteArray, 0, 1024);
clientOutput.write(myByteArray, 0, 1024);
clientOutput.flush();
*/
for(long i = 0; i <= myFile.length(); i += 1024)
{
byte[] myByteArray = new byte[1024];
bis.read(myByteArray, 0, 1024);
clientOutput.write(myByteArray, 0, 1024);
clientOutput.flush();
System.out.println("i is: " + i);
}
System.out.println("File Written");
sock.close();
} catch (IOException ex)
{
Logger.getLogger(TCPClient.class.getName()).log(Level.SEVERE, null, ex);
System.out.println("You can't do that!");
}
System.out.println("Finished");
}
}
服务器
import java.io.*;
import java.net.*;
public class RequestHandler
{
public void handleRequest()
{
try
{
ServerSocket welcomeSocket = new ServerSocket(8899);
while(true)
{
Socket socket = welcomeSocket.accept();
System.out.println("Socket Open");
/* Create byte array */
byte[] mybytearray = new byte[1024 * 512];
/* Create streams */
InputStream is = socket.getInputStream();
FileOutputStream fos = new FileOutputStream("newFile.txt",true);
BufferedOutputStream bos = new BufferedOutputStream(fos);
/*Write to file*/
int bytesRead = is.read(mybytearray, 0, mybytearray.length);
bos.write(mybytearray, 0, bytesRead);
/*Close Stream and Socket*/
bos.close();
socket.close();
}
} catch (Exception e)
{
e.printStackTrace();
}
}
public static void main(String args[])
{
RequestHandler rq = new RequestHandler();
rq.handleRequest();
System.out.println("Here");
}
}
答案 0 :(得分:1)
您的复制技术不正确。这是如何在Java中复制流:
byte[] buffer = new byte[8192]; // or whatever you like, but declare it outside the loop
int count;
while ((count = in.read(buffer)) > 0)
{
out.write(buffer, 0, count);
}
out.flush();
// then in a finally block ...
out.close();
in.close();
两端都需要这个。您不能假设任何给定的读取将填充缓冲区,因此您必须循环直到EOS。请注意,不会在循环内刷新。