Question

我有一个很好的查询，效果很好：

select distinct f.client_id
from f_accession_daily f
left join SalesDWH..TestPractices tests
on tests.ClientID=f.CLIENT_ID
where tests.ClientID is null
group by f.client_id
having max(f.received_date) between '20120601' and '20120630'

我需要将结果集限制为仅f.client_id，其中特定f.client_id的计数（*）在过去一个月（即'20120501'和'之间）为40或更高20120530' ）

这是我试过的：

select distinct f.client_id
from f_accession_daily f
left join SalesDWH..TestPractices tests
on tests.ClientID=f.CLIENT_ID
where tests.ClientID is null
group by f.client_id
having max(f.received_date) between '20120601' and '20120630'
) NotOrderedIn6Months
on f.CLIENT_ID=NotOrderedIn6Months.CLIENT_ID
right join
(select client_id,COUNT(*) count from F_ACCESSION_DAILY
where RECEIVED_DATE between '20120501' and '20120530'
group by CLIENT_ID
having COUNT(*)>=40
) Having40
on Having40.CLIENT_ID=f.CLIENT_ID

Answer 1

预先汇总上个月的数据（5月份有31天，而不是30天），然后加入。

   select f.client_id
     from f_accession_daily f
     join (
        select client_id
          from f_accession_daily
         where received_date between '20120501' and '20120531'
      group by client_id
        having count(*) >= 40
      ) A on A.client_id = f.client_id
left join SalesDWH..TestPractices tests
       on tests.ClientID=f.CLIENT_ID
    where tests.ClientID is null
 group by f.client_id
   having max(f.received_date) between '20120601' and '20120630';

另请注意，当您已经拥有GROUP BY时，您将不需要DISTINCT。

Answer 2

添加

AND f.client_id IN
(SELECT client_id FROM F_ACCESSION_DAILY
WHERE RECEIVED_DATE BETWEEN '20120501' AND '20120530'
GROUP BY client_id
HAVING COUNT(*) >= 40)

到原始查询的where子句。

在HAVING查询中添加过滤器

2 个答案: