我想从计数结果中获取AVG。
SELECT labelname AS Record_Labels, COUNT(title) AS Number_of_CDs_Released FROM CD
JOIN RecordLabel ON labelname = released_by
GROUP BY labelname;
我试过这样做:AVG(COUNT(标题)),但它没有用。任何人都可以帮助我吗?
答案 0 :(得分:4)
您可以使用嵌套查询执行此操作:
select avg(Number_of_CDs_Released) from
(SELECT labelname AS Record_Labels, COUNT(title) AS Number_of_CDs_Released FROM CD
JOIN RecordLabel ON labelname = released_by
GROUP BY labelname) nested;