Question

大家好，我正在连接这样的JSON字符串：

      var addresses = "[";

         addresses += '{"AddressID":' + adressid + ',"EmailID":' + $('#txtemailData').val() + ',"Hno":' + $('#txthno').val() + ',"StreetName":' + $('#txtstreetname').val() + ',"City":' + $('#txtcity').val() + ',"StateID":' + $('#ddlState').val() + ',"CountryID":' + $('#ddlcountry').val() + ',"Zip":' + $('#txtzip').val() + ',"PhoneNumber":' + $('#txtphonenumber').val() + ',"Fax":' + $('#txtfax').val() + ',"AddressName:' + $('#txtaddresstype').val() + '"},';

对象看起来像这样：

[{
   "AddressID":2,
   "EmailID":akanilkumar443@gmail.com,
   "Hno":Hyderabad,
   "StreetName":Gachibowli,
   "City":Hyderabad,
   "StateID":1,
   "CountryID":1,
   "Zip":040,
   "PhoneNumber":8341516166,
   "Fax":23123131,
   "AddressName:Store Address"},
 { 
   "AddressID":3,
   "EmailID":akanilkumar443@gmail.com,
   "Hno":aSAs,
   "StreetName":asdasdad,
   "City":asdasda,
   "StateID":1,
   "CountryID":1,
   "Zip":asdasda,
   "PhoneNumber":asdasda,
   "Fax":asdasda,
"AddressName:Store Type"
}]

如何基于它的id更新json对象的这个特定值？

假设我想要更改对象的某些值其中AddressID=2。例如，我想更改EmailID Streetname个JSON个AddressID=2个对象。我怎么能用jQuery做到这一点？

我正在尝试这样，但它不会循环，任何人都可以帮助我吗？

    function EditAddress(addressid) {
    alert(addressid);
    alert(addresses);
    var addressobject =JSON.parse(addresses.substring(0, addresses.length - 1) + ']');
    jQuery.each(addressobject, function (i, val) {
        alert(val.AddressID);
        if (val.AddressID == addressid) 
        {
            //update logic
        }
    });
}

Answer 1

这很简单。这是一个例子：

var testObject = [
        {"id": "1", "name": "Apple"  , "isVisible": false},
        {"id": "2", "name": "Orange", "isVisible": false}
    ]

$(testObject).each(function() {
    if(this.id == 2){
      alert("current " + this.id + " = " + this.isVisible);
      this.isVisible = true;
      alert("changed " + this.id + " = " + this.isVisible);
    }
});

Answer 2

首先不要手工创建字符串。使用内置功能会更加健壮，所以这样做：

var addressesAsArray = [],
    addressAsObject = {}
    address;
//assuming some loop or other
address = {
              "AddressID": adressid,
              "EmailID":$('#txtemailData').val(),
              "Hno":$('#txthno').val(),
              "StreetName": $('#txtstreetname').val(),
              "City": $('#txtcity').val(),
              "StateID": $('#ddlState').val(),
              "CountryID": $('#ddlcountry').val(),
              "Zip": $('#txtzip').val(),
              "PhoneNumber": $('#txtphonenumber').val(),
              "Fax": $('#txtfax').val(),
              "AddressName": $('#txtaddresstype').val()
          };
addressesAsArray.push(address);
addressAsObject[address.AddressID] = address;

如果您需要查找具有给定ID的地址，那么该方法将取决于您是在查找addressAsArray还是在addressesAsObject中查找。后者是直截了当的

address = addressesAsObject[addressIDBeingSought];

在数组中你可以简单地循环

for(i = 0, len = addressesAsArray.length;i<len; i += 1){
   if(addressesAsArray[i].AddressID === addressIDBeingSought) {
       address = addressesAsArray[i];
       break;
   }
}

完成更新后，您可以通过

将其作为JSON

json = JSON.stringify(adresses);

Answer 3

使用linq.js javascript库或jquery插件：http://linqjs.codeplex.com/

    <!DOCTYPE>
    <html>
    <head>
        <script type="text/javascript" src="linq.js"></script>
    </head>
    <body>
    <script>  
    var array = [{
       AddressID:2,
       EmailID:'akanilkumar443@gmail.com',
       Hno:'Hyderabad'
       },
     { 
       AddressID:3,
       EmailID:'akanilkumar443@gmail.com',
       Hno:'aSAs'
    }];
    Enumerable.From(array).Where("$.AddressID == 3").ToArray()[0].Hno= 'ololo'; 
// or this: 
// Enumerable.From(array).Where(function(x){return x.AddressID == 3}).ToArray()[0].Hno= 'ololo'; 
    alert(array[1].Hno)  
    </script>
    </body>
    </html>

如何使用jQuery更新Json对象？

3 个答案: