我已经研究了好几天了。我总是得到这样的东西(这是我认为最好的答案):
SELECT `COLUMN_NAME`
FROM `INFORMATION_SCHEMA`.`COLUMNS`
WHERE `TABLE_SCHEMA`='yourdatabasename'
AND `TABLE_NAME`='yourtablename';
是的,这个在SQL中完美运行,但我仍然不知道如何创建一个PHP脚本来显示它与在SQL中一样。谁能给我一个代码?
我现在真的很困惑。请帮忙..
答案 0 :(得分:2)
没有PDO:
$sql = "SHOW FIELDS FROM users;";
$result_sql = mysql_query($sql) or die ("Error!\n");
while ($row = mysql_fetch_array($result_sql)) {
echo $row['Field']."<br>\n";
}
答案 1 :(得分:1)
您可以在mysql mysql_field_name()
不鼓励使用mysql_*
,因此请使用pdo
或mysqli
与他们一起你可以通过
来做到这一点mysqli_fetch_field_direct() //for mysqli
PDOStatement::getColumnMeta() //for pdo
例如在OP comment
之后$sql = "SELECT * from Person";
$result = mysql_query($sql,$con);
$name = mysql_field_name($result, 0);
解释如何使用mysql_field_name()
<强>了Syntex 强>
mysql_field_name(data,fieldOffset)
+------------+------------------------------------------------------------------+
| data | Required. Specifies which data pointer to use. The data |
| | pointer is the result from the mysql_query() function |
+------------+------------------------------------------------------------------+
|fieldOffset |Required. Specifies which field to start returning. 0 indicates |
| |the first field |
+------------+------------------------------------------------------------------+
好读
答案 2 :(得分:1)
显然你需要从mysql表中检索数据,然后用php做一些事情。有几种方法可以做到这一点,这是我的最爱:
<?php
$query="SELECT `COLUMN_NAME`
FROM `INFORMATION_SCHEMA`.`COLUMNS`
WHERE `TABLE_SCHEMA`='yourdatabasename'
AND `TABLE_NAME`='yourtablename'";
$result=mysql_query($query); //This will store the whole result table in $result
$rows=array(); //Initialize array
while($row=mysql_fetch_object($result)) $rows[]=(object) $row; //Store each row of the result table in the array $rows
//Now you can access, for example, the third row and second column by saying:
echo $rows[2]->name_of_second_column
?>
另请参阅this tutorial.,了解如何从数据库中检索数据并在之后对其进行操作。