我正在尝试将以下查询移至Linq-to-sql,是否可能?
select * from (
Select top (@Percent) percent with ties *
from(
Select distinct
LoanNumber as LoanNo
From CHE
Left Join RecordingInfo as Rec
On CHE.LoanNumber = Rec.LoanNo
Where Channel = 'LINX'
and CHE.Doc in ('MTG','MOD')
and Rec.LoanNo is null
and LoanNumber >= '@LoanNo'
) A
order by LoanNo @Order
) B
order by LoanNo
我还没有看到linq中的关系。
答案 0 :(得分:3)
我认为这样的事情对你有用。
public static IQueryable<T> TopPercentWithTies<T, TKey>(this IOrderedQueryable<T> query, Expression<Func<T, TKey>> groupByExpression, double percent)
{
var groupedQuery = query.GroupBy(groupByExpression);
int numberToTake = groupedQuery.Count() * percent / 100;
return groupedQuery.Take(numberToTake).SelectMany(t => t);
}
我只用IEnumerable测试过,所以我不确定它是否可以正常使用IQueryable。我还在调用TopPercentWithTies()之前对列表进行了排序。
这是我用来测试它的代码。
int percent = 50;
var people = new []
{
new { Age = 99, Name = "Adam" },
new { Age = 99, Name = "Andrew" },
new { Age = 89, Name = "Bob" },
new { Age = 50, Name = "Cecil" },
new { Age = 50, Name = "Doug" },
new { Age = 50, Name = "Everett" },
new { Age = 35, Name = "Frank" },
new { Age = 25, Name = "Greg" },
new { Age = 15, Name = "Hank" }
};
var sortedPeople = people.AsQueryable().OrderByDescending(person => person.Age);
var results = sortedPeople.TopPercentWithTies(person => person.Age, percent);
foreach (var person in results)
Console.WriteLine(person);
希望它有助于或至少让您朝着正确的方向前进。您可能想要调整计算numberToTake的逻辑。