Question

我需要在页面重新加载时保持选定值的持久性。我正在使用带有jQuery的多选插件作为下拉选择菜单。这可能吗？我不太了解这一点，所以如果我听起来很蠢，抱歉。：）

<select multiple="multiple" style="width: 135px;" name="platform[]" id="platform">
<option value="platform_1">Platform 1</option>
<option value="platform_2">Platform 2</option>
</select>

<select id="2" multiple="multiple" style="width: 165px;" name="features[]" id="features">
<optgroup label="Group One">
<option value="feature_1">Feature 1</option>
<option value="feature_2">Feature 2</option>
<option value="feature_3">Feature 3</option>
<option value="feature_4">Feature 4</option>
<option value="feature_5">Feature 5</option>
<optgroup label="Group Two">
<option value="feature_6">Feature 6</option>
<option value="feature_7">Feature 7</option>
<option value="feature_8">Feature 8</option>
</select>

Answer 1

以下是您可能需要的示例：

$("#platform").val(getCookie("platform"));
$("#2").val(getCookie("feature"));

$("#platform option").click(function(){
    document.cookie = "platform="+$(this).val();
});
$("#2 option").click(function(){
    document.cookie = "feature="+$(this).val();
});

function getCookie(c_name) {
var i,x,y,ARRcookies=document.cookie.split(";");
for (i=0;i<ARRcookies.length;i++) {
 x=ARRcookies[i].substr(0,ARRcookies[i].indexOf("="));
 y=ARRcookies[i].substr(ARRcookies[i].indexOf("=")+1);
  x=x.replace(/^\s+|\s+$/g,"");
  if (x==c_name)
    {
    return unescape(y);
    }
  }
}

jsfiddle

保持选择持久

1 个答案: