MATLAB - 矩阵维度必须一致(尽管它们是“同意的”!)

时间:2012-11-09 18:27:40

标签: matlab vector matrix

以下是代码:

fs = 22050;
x = rand(fs,1);
x = x - mean(x); % get rid of DC offeset

% set comb-filter coefficients
f = 220; % fundamental
L = round(fs/f); % delay length 
coef = 0.99; % IIR coefficient

% build delay vector and filter 
b = [1 zeros(1,L-1) coef];
y = filter(1, b, x);

% create amplitude envelope for output 
decay = 8;
expEnv = exp ((0:(length(y)-1))/length(y));
expEnv = (1./expEnv).^ decay;
fprintf('%d\n',length(expEnv));
fprintf('%d\n', length(y));

% envelope output signal
z = y .* expEnv;
sound(z , fs); % play sound

它拒绝执行z = y。* expEnv行。 printf行显示y和expEnv具有相同的长度(22050)

1 个答案:

答案 0 :(得分:4)

是...... length命令的危险。

虽然它们具有相同数量的元素,但具有相同的形状:

>> size(y)
ans =
       22050           1
>> size(expEnv)
ans =
           1       22050

这将解决这个问题:

z = y .* expEnv.';